Given an array of integers cost and an integer target, return the maximum integer you can paint under the following rules:
(i + 1) is given by cost[i] (0-indexed).target.0 digits.Since the answer may be very large, return it as a string. If there is no way to paint any integer given the condition, return "0".
\n
Example 1:
\n\n\nInput: cost = [4,3,2,5,6,7,2,5,5], target = 9\nOutput: "7772"\nExplanation: The cost to paint the digit '7' is 2, and the digit '2' is 3. Then cost("7772") = 2*3+ 3*1 = 9. You could also paint "977", but "7772" is the largest number.\nDigit cost\n 1 -> 4\n 2 -> 3\n 3 -> 2\n 4 -> 5\n 5 -> 6\n 6 -> 7\n 7 -> 2\n 8 -> 5\n 9 -> 5\n\n\nExample 2:
\n\n\nInput: cost = [7,6,5,5,5,6,8,7,8], target = 12\nOutput: "85"\nExplanation: The cost to paint the digit '8' is 7, and the digit '5' is 5. Then cost("85") = 7 + 5 = 12.\n\n\nExample 3:
\n\n\nInput: cost = [2,4,6,2,4,6,4,4,4], target = 5\nOutput: "0"\nExplanation: It is impossible to paint any integer with total cost equal to target.\n\n\n
\n
Constraints:
\n\ncost.length == 91 <= cost[i], target <= 5000Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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