Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array nums = [0,1,4,4,5,6,7] might become:
[4,5,6,7,0,1,4] if it was rotated 4 times.[0,1,4,4,5,6,7] if it was rotated 7 times.Notice that rotating an array [a[0], a[1], a[2], ..., a[n-1]] 1 time results in the array [a[n-1], a[0], a[1], a[2], ..., a[n-2]].
Given the sorted rotated array nums that may contain duplicates, return the minimum element of this array.
You must decrease the overall operation steps as much as possible.
\n\n\n
Example 1:
\nInput: nums = [1,3,5]\nOutput: 1\n
Example 2:
\nInput: nums = [2,2,2,0,1]\nOutput: 0\n\n
\n
Constraints:
\n\nn == nums.length1 <= n <= 5000-5000 <= nums[i] <= 5000nums is sorted and rotated between 1 and n times.\n
Follow up: This problem is similar to Find Minimum in Rotated Sorted Array, but nums may contain duplicates. Would this affect the runtime complexity? How and why?
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