There is a bi-directional graph with n vertices, where each vertex is labeled from 0 to n - 1 (inclusive). The edges in the graph are represented as a 2D integer array edges, where each edges[i] = [ui, vi] denotes a bi-directional edge between vertex ui and vertex vi. Every vertex pair is connected by at most one edge, and no vertex has an edge to itself.
You want to determine if there is a valid path that exists from vertex source to vertex destination.
Given edges and the integers n, source, and destination, return true if there is a valid path from source to destination, or false otherwise.
\n
Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2021/08/14/validpath-ex1.png\")
\n\nInput: n = 3, edges = [[0,1],[1,2],[2,0]], source = 0, destination = 2\nOutput: true\nExplanation: There are two paths from vertex 0 to vertex 2:\n- 0 → 1 → 2\n- 0 → 2\n\n\n
Example 2:
\n![\"\"](\"https://assets.leetcode.com/uploads/2021/08/14/validpath-ex2.png\")
\n\nInput: n = 6, edges = [[0,1],[0,2],[3,5],[5,4],[4,3]], source = 0, destination = 5\nOutput: false\nExplanation: There is no path from vertex 0 to vertex 5.\n\n\n
\n
Constraints:
\n\n1 <= n <= 2 * 1050 <= edges.length <= 2 * 105edges[i].length == 20 <= ui, vi <= n - 1ui != vi0 <= source, destination <= n - 1Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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