Given a list of strings words and a string pattern, return a list of words[i] that match pattern. You may return the answer in any order.
A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the desired word.
Recall that a permutation of letters is a bijection from letters to letters: every letter maps to another letter, and no two letters map to the same letter.
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Example 1:
\n\n\nInput: words = ["abc","deq","mee","aqq","dkd","ccc"], pattern = "abb"\nOutput: ["mee","aqq"]\nExplanation: "mee" matches the pattern because there is a permutation {a -> m, b -> e, ...}. \n"ccc" does not match the pattern because {a -> c, b -> c, ...} is not a permutation, since a and b map to the same letter.\n\n\nExample 2:
\n\n\nInput: words = ["a","b","c"], pattern = "a"\nOutput: ["a","b","c"]\n\n\n
\n
Constraints:
\n\n1 <= pattern.length <= 201 <= words.length <= 50words[i].length == pattern.lengthpattern and words[i] are lowercase English letters.Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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