You are given a 0-indexed array nums consisting of positive integers, representing targets on a number line. You are also given an integer space.
You have a machine which can destroy targets. Seeding the machine with some nums[i] allows it to destroy all targets with values that can be represented as nums[i] + c * space, where c is any non-negative integer. You want to destroy the maximum number of targets in nums.
Return the minimum value of nums[i] you can seed the machine with to destroy the maximum number of targets.
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Example 1:
\n\n\nInput: nums = [3,7,8,1,1,5], space = 2\nOutput: 1\nExplanation: If we seed the machine with nums[3], then we destroy all targets equal to 1,3,5,7,9,... \nIn this case, we would destroy 5 total targets (all except for nums[2]). \nIt is impossible to destroy more than 5 targets, so we return nums[3].\n\n\n
Example 2:
\n\n\nInput: nums = [1,3,5,2,4,6], space = 2\nOutput: 1\nExplanation: Seeding the machine with nums[0], or nums[3] destroys 3 targets. \nIt is not possible to destroy more than 3 targets.\nSince nums[0] is the minimal integer that can destroy 3 targets, we return 1.\n\n\n
Example 3:
\n\n\nInput: nums = [6,2,5], space = 100\nOutput: 2\nExplanation: Whatever initial seed we select, we can only destroy 1 target. The minimal seed is nums[1].\n\n\n
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Constraints:
\n\n1 <= nums.length <= 1051 <= nums[i] <= 1091 <= space <= 109Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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