Given the root of a binary tree, return the sum of every tree node's tilt.
The tilt of a tree node is the absolute difference between the sum of all left subtree node values and all right subtree node values. If a node does not have a left child, then the sum of the left subtree node values is treated as 0. The rule is similar if the node does not have a right child.
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Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2020/10/20/tilt1.jpg\")
\n\nInput: root = [1,2,3]\nOutput: 1\nExplanation: \nTilt of node 2 : |0-0| = 0 (no children)\nTilt of node 3 : |0-0| = 0 (no children)\nTilt of node 1 : |2-3| = 1 (left subtree is just left child, so sum is 2; right subtree is just right child, so sum is 3)\nSum of every tilt : 0 + 0 + 1 = 1\n\n\n
Example 2:
\n![\"\"](\"https://assets.leetcode.com/uploads/2020/10/20/tilt2.jpg\")
\n\nInput: root = [4,2,9,3,5,null,7]\nOutput: 15\nExplanation: \nTilt of node 3 : |0-0| = 0 (no children)\nTilt of node 5 : |0-0| = 0 (no children)\nTilt of node 7 : |0-0| = 0 (no children)\nTilt of node 2 : |3-5| = 2 (left subtree is just left child, so sum is 3; right subtree is just right child, so sum is 5)\nTilt of node 9 : |0-7| = 7 (no left child, so sum is 0; right subtree is just right child, so sum is 7)\nTilt of node 4 : |(3+5+2)-(9+7)| = |10-16| = 6 (left subtree values are 3, 5, and 2, which sums to 10; right subtree values are 9 and 7, which sums to 16)\nSum of every tilt : 0 + 0 + 0 + 2 + 7 + 6 = 15\n\n\n
Example 3:
\n![\"\"](\"https://assets.leetcode.com/uploads/2020/10/20/tilt3.jpg\")
\n\nInput: root = [21,7,14,1,1,2,2,3,3]\nOutput: 9\n\n\n
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Constraints:
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