You are given the root of a binary tree with unique values, and an integer start. At minute 0, an infection starts from the node with value start.
Each minute, a node becomes infected if:
\n\nReturn the number of minutes needed for the entire tree to be infected.
\n\n\n
Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2022/06/25/image-20220625231744-1.png\")
\n\nInput: root = [1,5,3,null,4,10,6,9,2], start = 3\nOutput: 4\nExplanation: The following nodes are infected during:\n- Minute 0: Node 3\n- Minute 1: Nodes 1, 10 and 6\n- Minute 2: Node 5\n- Minute 3: Node 4\n- Minute 4: Nodes 9 and 2\nIt takes 4 minutes for the whole tree to be infected so we return 4.\n\n\n
Example 2:
\n![\"\"](\"https://assets.leetcode.com/uploads/2022/06/25/image-20220625231812-2.png\")
\n\nInput: root = [1], start = 1\nOutput: 0\nExplanation: At minute 0, the only node in the tree is infected so we return 0.\n\n\n
\n
Constraints:
\n\n[1, 105].1 <= Node.val <= 105start exists in the tree.Compiled with clang 11 using the latest C++ 20 standard.
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