English description is not available for the problem. Please switch to Chinese.
\n", "translatedTitle": "打开转盘锁", "translatedContent": "一个密码锁由 4 个环形拨轮组成，每个拨轮都有 10 个数字： '0', '1', '2', '3', '4', '5', '6', '7', '8', '9' 。每个拨轮可以自由旋转：例如把 '9' 变为 '0'，'0' 变为 '9' 。每次旋转都只能旋转一个拨轮的一位数字。
锁的初始数字为 '0000' ，一个代表四个拨轮的数字的字符串。
列表 deadends 包含了一组死亡数字，一旦拨轮的数字和列表里的任何一个元素相同，这个锁将会被永久锁定，无法再被旋转。
字符串 target 代表可以解锁的数字，请给出解锁需要的最小旋转次数，如果无论如何不能解锁，返回 -1 。
\n\n
示例 1:
\n\n\n输入：deadends = ["0201","0101","0102","1212","2002"], target = "0202"\n输出：6\n解释：\n可能的移动序列为 "0000" -> "1000" -> "1100" -> "1200" -> "1201" -> "1202" -> "0202"。\n注意 "0000" -> "0001" -> "0002" -> "0102" -> "0202" 这样的序列是不能解锁的，因为当拨动到 "0102" 时这个锁就会被锁定。\n\n\n
示例 2:
\n\n\n输入: deadends = ["8888"], target = "0009"\n输出：1\n解释：\n把最后一位反向旋转一次即可 "0000" -> "0009"。\n\n\n
示例 3:
\n\n\n输入: deadends = ["8887","8889","8878","8898","8788","8988","7888","9888"], target = "8888"\n输出：-1\n解释：\n无法旋转到目标数字且不被锁定。\n\n\n
示例 4:
\n\n\n输入: deadends = ["0000"], target = "8888"\n输出：-1\n\n\n
\n\n
提示：
\n\n1 <= deadends.length <= 500deadends[i].length == 4target.length == 4target 不在 deadends 之中target 和 deadends[i] 仅由若干位数字组成\n\n
注意：本题与主站 752 题相同： https://leetcode-cn.com/problems/open-the-lock/
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