{ "data": { "question": { "questionId": "1023", "questionFrontendId": "981", "categoryTitle": "Algorithms", "boundTopicId": 2910, "title": "Time Based Key-Value Store", "titleSlug": "time-based-key-value-store", "content": "
Design a time-based key-value data structure that can store multiple values for the same key at different time stamps and retrieve the key's value at a certain timestamp.
\n\nImplement the TimeMap
class:
TimeMap()
Initializes the object of the data structure.void set(String key, String value, int timestamp)
Stores the key key
with the value value
at the given time timestamp
.String get(String key, int timestamp)
Returns a value such that set
was called previously, with timestamp_prev <= timestamp
. If there are multiple such values, it returns the value associated with the largest timestamp_prev
. If there are no values, it returns ""
.\n
Example 1:
\n\n\nInput\n["TimeMap", "set", "get", "get", "set", "get", "get"]\n[[], ["foo", "bar", 1], ["foo", 1], ["foo", 3], ["foo", "bar2", 4], ["foo", 4], ["foo", 5]]\nOutput\n[null, null, "bar", "bar", null, "bar2", "bar2"]\n\nExplanation\nTimeMap timeMap = new TimeMap();\ntimeMap.set("foo", "bar", 1); // store the key "foo" and value "bar" along with timestamp = 1.\ntimeMap.get("foo", 1); // return "bar"\ntimeMap.get("foo", 3); // return "bar", since there is no value corresponding to foo at timestamp 3 and timestamp 2, then the only value is at timestamp 1 is "bar".\ntimeMap.set("foo", "bar2", 4); // store the key "foo" and value "bar2" along with timestamp = 4.\ntimeMap.get("foo", 4); // return "bar2"\ntimeMap.get("foo", 5); // return "bar2"\n\n\n
\n
Constraints:
\n\n1 <= key.length, value.length <= 100
key
and value
consist of lowercase English letters and digits.1 <= timestamp <= 107
timestamp
of set
are strictly increasing.2 * 105
calls will be made to set
and get
.设计一个基于时间的键值数据结构,该结构可以在不同时间戳存储对应同一个键的多个值,并针对特定时间戳检索键对应的值。
\n\n实现 TimeMap
类:
TimeMap()
初始化数据结构对象void set(String key, String value, int timestamp)
存储给定时间戳 timestamp
时的键 key
和值 value
。String get(String key, int timestamp)
返回一个值,该值在之前调用了 set
,其中 timestamp_prev <= timestamp
。如果有多个这样的值,它将返回与最大 timestamp_prev
关联的值。如果没有值,则返回空字符串(\"\"
)。示例 1:
\n\n\n输入:\n[\"TimeMap\", \"set\", \"get\", \"get\", \"set\", \"get\", \"get\"]\n[[], [\"foo\", \"bar\", 1], [\"foo\", 1], [\"foo\", 3], [\"foo\", \"bar2\", 4], [\"foo\", 4], [\"foo\", 5]]\n输出:\n[null, null, \"bar\", \"bar\", null, \"bar2\", \"bar2\"]\n\n解释:\nTimeMap timeMap = new TimeMap();\ntimeMap.set(\"foo\", \"bar\", 1); // 存储键 \"foo\" 和值 \"bar\" ,时间戳 timestamp = 1 \ntimeMap.get(\"foo\", 1); // 返回 \"bar\"\ntimeMap.get(\"foo\", 3); // 返回 \"bar\", 因为在时间戳 3 和时间戳 2 处没有对应 \"foo\" 的值,所以唯一的值位于时间戳 1 处(即 \"bar\") 。\ntimeMap.set(\"foo\", \"bar2\", 4); // 存储键 \"foo\" 和值 \"bar2\" ,时间戳 timestamp = 4 \ntimeMap.get(\"foo\", 4); // 返回 \"bar2\"\ntimeMap.get(\"foo\", 5); // 返回 \"bar2\"\n\n\n
\n\n
提示:
\n\n1 <= key.length, value.length <= 100
key
和 value
由小写英文字母和数字组成1 <= timestamp <= 107
set
操作中的时间戳 timestamp
都是严格递增的set
和 get
操作 2 * 105
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out-of-bounds<\\/code>\\u548c
use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
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Python 2.7.12<\\/code><\\/p>\\r\\n\\r\\n
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out-of-bounds<\\/code>\\u548c
use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
\\r\\nstruct hash_entry {\\r\\n int id; \\/* we'll use this field as the key *\\/\\r\\n char name[10];\\r\\n UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n
\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n struct hash_entry *s;\\r\\n HASH_FIND_INT(users, &user_id, s);\\r\\n return s;\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n
\\r\\nvoid delete_user(struct hash_entry *user) {\\r\\n HASH_DEL(users, user); \\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\"],\"csharp\":[\"C#\",\"
Node.js 16.13.2<\\/code><\\/p>\\r\\n\\r\\n
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Python 3.10<\\/code><\\/p>\\r\\n\\r\\n
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Kotlin 1.9.0<\\/code><\\/p>\\r\\n\\r\\n
rust 1.58.1<\\/code><\\/p>\\r\\n\\r\\n
PHP 8.1<\\/code>.<\\/p>\\r\\n\\r\\n