An attendance record for a student can be represented as a string where each character signifies whether the student was absent, late, or present on that day. The record only contains the following three characters:
\n\n'A': Absent.'L': Late.'P': Present.Any student is eligible for an attendance award if they meet both of the following criteria:
\n\n'A') for strictly fewer than 2 days total.'L') for 3 or more consecutive days.Given an integer n, return the number of possible attendance records of length n that make a student eligible for an attendance award. The answer may be very large, so return it modulo 109 + 7.
\n
Example 1:
\n\n\nInput: n = 2\nOutput: 8\nExplanation: There are 8 records with length 2 that are eligible for an award:\n"PP", "AP", "PA", "LP", "PL", "AL", "LA", "LL"\nOnly "AA" is not eligible because there are 2 absences (there need to be fewer than 2).\n\n\n
Example 2:
\n\n\nInput: n = 1\nOutput: 3\n\n\n
Example 3:
\n\n\nInput: n = 10101\nOutput: 183236316\n\n\n
\n
Constraints:
\n\n1 <= n <= 105'A'：Absent，缺勤'L'：Late，迟到'P'：Present，到场如果学生能够 同时 满足下面两个条件，则可以获得出勤奖励：
\n\n'A'）严格 少于两天。'L'）记录。给你一个整数 n ，表示出勤记录的长度（次数）。请你返回记录长度为 n 时，可能获得出勤奖励的记录情况 数量 。答案可能很大，所以返回对 109 + 7 取余 的结果。
\n\n
示例 1：
\n\n\n输入：n = 2\n输出：8\n解释：\n有 8 种长度为 2 的记录将被视为可奖励：\n\"PP\" , \"AP\", \"PA\", \"LP\", \"PL\", \"AL\", \"LA\", \"LL\" \n只有\"AA\"不会被视为可奖励，因为缺勤次数为 2 次（需要少于 2 次）。\n\n\n
示例 2：
\n\n\n输入：n = 1\n输出：3\n\n\n
示例 3：
\n\n\n输入：n = 10101\n输出：183236316\n\n\n
\n\n
提示：
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