You have an inventory of different colored balls, and there is a customer that wants orders balls of any color.
The customer weirdly values the colored balls. Each colored ball's value is the number of balls of that color you currently have in your inventory. For example, if you own 6 yellow balls, the customer would pay 6 for the first yellow ball. After the transaction, there are only 5 yellow balls left, so the next yellow ball is then valued at 5 (i.e., the value of the balls decreases as you sell more to the customer).
You are given an integer array, inventory, where inventory[i] represents the number of balls of the ith color that you initially own. You are also given an integer orders, which represents the total number of balls that the customer wants. You can sell the balls in any order.
Return the maximum total value that you can attain after selling orders colored balls. As the answer may be too large, return it modulo 109 + 7.
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Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2020/11/05/jj.gif\")
\n\nInput: inventory = [2,5], orders = 4\nOutput: 14\nExplanation: Sell the 1st color 1 time (2) and the 2nd color 3 times (5 + 4 + 3).\nThe maximum total value is 2 + 5 + 4 + 3 = 14.\n\n\n
Example 2:
\n\n\nInput: inventory = [3,5], orders = 6\nOutput: 19\nExplanation: Sell the 1st color 2 times (3 + 2) and the 2nd color 4 times (5 + 4 + 3 + 2).\nThe maximum total value is 3 + 2 + 5 + 4 + 3 + 2 = 19.\n\n\n
\n
Constraints:
\n\n1 <= inventory.length <= 1051 <= inventory[i] <= 1091 <= orders <= min(sum(inventory[i]), 109)你有一些球的库存 inventory ，里面包含着不同颜色的球。一个顾客想要 任意颜色 总数为 orders 的球。
这位顾客有一种特殊的方式衡量球的价值：每个球的价值是目前剩下的 同色球 的数目。比方说还剩下 6 个黄球，那么顾客买第一个黄球的时候该黄球的价值为 6 。这笔交易以后，只剩下 5 个黄球了，所以下一个黄球的价值为 5 （也就是球的价值随着顾客购买同色球是递减的）
给你整数数组 inventory ，其中 inventory[i] 表示第 i 种颜色球一开始的数目。同时给你整数 orders ，表示顾客总共想买的球数目。你可以按照 任意顺序 卖球。
请你返回卖了 orders 个球以后 最大 总价值之和。由于答案可能会很大，请你返回答案对 109 + 7 取余数 的结果。
\n\n
示例 1：
\n![\"\"](\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/11/08/jj.gif\")
\n\n输入：inventory = [2,5], orders = 4\n输出：14\n解释：卖 1 个第一种颜色的球（价值为 2 )，卖 3 个第二种颜色的球（价值为 5 + 4 + 3）。\n最大总和为 2 + 5 + 4 + 3 = 14 。\n\n\n
示例 2：
\n\n\n输入：inventory = [3,5], orders = 6\n输出：19\n解释：卖 2 个第一种颜色的球（价值为 3 + 2），卖 4 个第二种颜色的球（价值为 5 + 4 + 3 + 2）。\n最大总和为 3 + 2 + 5 + 4 + 3 + 2 = 19 。\n\n\n
示例 3：
\n\n\n输入：inventory = [2,8,4,10,6], orders = 20\n输出：110\n\n\n
示例 4：
\n\n\n输入：inventory = [1000000000], orders = 1000000000\n输出：21\n解释：卖 1000000000 次第一种颜色的球，总价值为 500000000500000000 。 500000000500000000 对 109 + 7 取余为 21 。\n\n\n
\n\n
提示：
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collections<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u6ce8\\u610f Python 2.7 \\u5c06\\u57282020\\u5e74\\u540e\\u4e0d\\u518d\\u7ef4\\u62a4<\\/a>\\u3002 \\u5982\\u60f3\\u4f7f\\u7528\\u6700\\u65b0\\u7248\\u7684Python\\uff0c\\u8bf7\\u9009\\u62e9Python 3\\u3002<\\/p>\"],\"c\":[\"C\",\" \\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n 1. 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