Given four integers sx, sy, tx, and ty, return true if it is possible to convert the point (sx, sy) to the point (tx, ty) through some operations, or false otherwise.
The allowed operation on some point (x, y) is to convert it to either (x, x + y) or (x + y, y).
\n
Example 1:
\n\n\nInput: sx = 1, sy = 1, tx = 3, ty = 5\nOutput: true\nExplanation:\nOne series of moves that transforms the starting point to the target is:\n(1, 1) -> (1, 2)\n(1, 2) -> (3, 2)\n(3, 2) -> (3, 5)\n\n\n
Example 2:
\n\n\nInput: sx = 1, sy = 1, tx = 2, ty = 2\nOutput: false\n\n\n
Example 3:
\n\n\nInput: sx = 1, sy = 1, tx = 1, ty = 1\nOutput: true\n\n\n
\n
Constraints:
\n\n1 <= sx, sy, tx, ty <= 109给定四个整数 sx , sy ，tx 和 ty，如果通过一系列的转换可以从起点 (sx, sy) 到达终点 (tx, ty)，则返回 true，否则返回 false。
从点 (x, y) 可以转换到 (x, x+y) 或者 (x+y, y)。
\n\n
示例 1:
\n\n\n输入: sx = 1, sy = 1, tx = 3, ty = 5\n输出: true\n解释:\n可以通过以下一系列转换从起点转换到终点：\n(1, 1) -> (1, 2)\n(1, 2) -> (3, 2)\n(3, 2) -> (3, 5)\n\n\n
示例 2:
\n\n\n输入: sx = 1, sy = 1, tx = 2, ty = 2 \n输出: false\n\n\n
示例 3:
\n\n\n输入: sx = 1, sy = 1, tx = 1, ty = 1 \n输出: true\n\n\n
\n\n
提示:
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\\u6a21\\u5757\\u4e2d\\u63d0\\u4f9b\\uff1ahttps:\\/\\/www.rubydoc.info\\/github\\/kanwei\\/algorithms\\/Algorithms<\\/p>\"],\"swift\":[\"Swift\",\" \\u7248\\u672c\\uff1a \\u6211\\u4eec\\u901a\\u5e38\\u4fdd\\u8bc1\\u66f4\\u65b0\\u5230 Apple\\u653e\\u51fa\\u7684\\u6700\\u65b0\\u7248Swift<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u53d1\\u73b0Swift\\u4e0d\\u662f\\u6700\\u65b0\\u7248\\u7684\\uff0c\\u8bf7\\u8054\\u7cfb\\u6211\\u4eec\\uff01\\u6211\\u4eec\\u5c06\\u5c3d\\u5feb\\u66f4\\u65b0\\u3002<\\/p>\"],\"golang\":[\"Go\",\" \\u7248\\u672c\\uff1a \\u652f\\u6301 https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982array<\\/a>, bisect<\\/a>, collections<\\/a>\\u3002 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