You are given an integer array nums. The adjacent integers in nums will perform the float division.
nums = [2,3,4], we will evaluate the expression "2/3/4".However, you can add any number of parenthesis at any position to change the priority of operations. You want to add these parentheses such the value of the expression after the evaluation is maximum.
\n\nReturn the corresponding expression that has the maximum value in string format.
\n\nNote: your expression should not contain redundant parenthesis.
\n\n\n
Example 1:
\n\n\nInput: nums = [1000,100,10,2]\nOutput: "1000/(100/10/2)"\nExplanation: 1000/(100/10/2) = 1000/((100/10)/2) = 200\nHowever, the bold parenthesis in "1000/((100/10)/2)" are redundant since they do not influence the operation priority.\nSo you should return "1000/(100/10/2)".\nOther cases:\n1000/(100/10)/2 = 50\n1000/(100/(10/2)) = 50\n1000/100/10/2 = 0.5\n1000/100/(10/2) = 2\n\n\n
Example 2:
\n\n\nInput: nums = [2,3,4]\nOutput: "2/(3/4)"\nExplanation: (2/(3/4)) = 8/3 = 2.667\nIt can be shown that after trying all possibilities, we cannot get an expression with evaluation greater than 2.667\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 102 <= nums[i] <= 1000给定一正整数数组 nums，nums 中的相邻整数将进行浮点除法。例如， [2,3,4] -> 2 / 3 / 4 。
nums = [2,3,4]，我们将求表达式的值 \"2/3/4\"。但是，你可以在任意位置添加任意数目的括号，来改变算数的优先级。你需要找出怎么添加括号，以便计算后的表达式的值为最大值。
\n\n以字符串格式返回具有最大值的对应表达式。
\n\n注意：你的表达式不应该包含多余的括号。
\n\n\n\n
示例 1：
\n\n\n输入: [1000,100,10,2]\n输出: \"1000/(100/10/2)\"\n解释: 1000/(100/10/2) = 1000/((100/10)/2) = 200\n但是，以下加粗的括号 \"1000/((100/10)/2)\" 是冗余的，\n因为他们并不影响操作的优先级，所以你需要返回 \"1000/(100/10/2)\"。\n\n其他用例:\n1000/(100/10)/2 = 50\n1000/(100/(10/2)) = 50\n1000/100/10/2 = 0.5\n1000/100/(10/2) = 2\n\n\n
\n\n
示例 2:
\n\n\n输入: nums = [2,3,4]\n输出: \"2/(3/4)\"\n解释: (2/(3/4)) = 8/3 = 2.667\n可以看出，在尝试了所有的可能性之后，我们无法得到一个结果大于 2.667 的表达式。\n\n\n
\n\n
说明:
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