You are given a 0-indexed integer array nums.
nums is the minimum value of |nums[i] - nums[j]| over all 0 <= i < j < nums.length.nums is the maximum value of |nums[i] - nums[j]| over all 0 <= i < j < nums.length.nums is the sum of the high and low scores of nums.To minimize the score of nums, we can change the value of at most two elements of nums.
Return the minimum possible score after changing the value of at most two elements of nums.
Note that |x| denotes the absolute value of x.
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Example 1:
\n\n\nInput: nums = [1,4,3]\nOutput: 0\nExplanation: Change value of nums[1] and nums[2] to 1 so that nums becomes [1,1,1]. Now, the value of |nums[i] - nums[j]| is always equal to 0, so we return 0 + 0 = 0.\n\n\nExample 2:
\n\n\nInput: nums = [1,4,7,8,5]\nOutput: 3\nExplanation: Change nums[0] and nums[1] to be 6. Now nums becomes [6,6,7,8,5].\nOur low score is achieved when i = 0 and j = 1, in which case |\n\nnums[i] - nums[j]| = |6 - 6| = 0.\nOur high score is achieved when i = 3 and j = 4, in which case |nums[i] - nums[j]| = |8 - 5| = 3.\nThe sum of our high and low score is 3, which we can prove to be minimal.\n
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Constraints:
\n\n3 <= nums.length <= 1051 <= nums[i] <= 109给你一个下标从 0 开始的整数数组 nums 。
nums 的 最小 得分是满足 0 <= i < j < nums.length 的 |nums[i] - nums[j]| 的最小值。nums的 最大 得分是满足 0 <= i < j < nums.length 的 |nums[i] - nums[j]| 的最大值。nums 的分数是 最大 得分与 最小 得分的和。我们的目标是最小化 nums 的分数。你 最多 可以修改 nums 中 2 个元素的值。
请你返回修改 nums 中 至多两个 元素的值后，可以得到的 最小分数 。
|x| 表示 x 的绝对值。
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示例 1：
\n\n\n输入：nums = [1,4,3]\n输出：0\n解释：将 nums[1] 和 nums[2] 的值改为 1 ，nums 变为 [1,1,1] 。|nums[i] - nums[j]| 的值永远为 0 ，所以我们返回 0 + 0 = 0 。\n\n\n示例 2：
\n\n\n输入：nums = [1,4,7,8,5]\n输出：3\n解释：\n将 nums[0] 和 nums[1] 的值变为 6 ，nums 变为 [6,6,7,8,5] 。\n最小得分是 i = 0 且 j = 1 时得到的 |\n\nnums[i] - nums[j]| = |6 - 6| = 0 。\n最大得分是 i = 3 且 j = 4 时得到的 |nums[i] - nums[j]| = |8 - 5| = 3 。\n最大得分与最小得分之和为 3 。这是最优答案。\n
\n\n
提示：
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