{ "data": { "question": { "questionId": "2266", "questionFrontendId": "2162", "categoryTitle": "Algorithms", "boundTopicId": 1243406, "title": "Minimum Cost to Set Cooking Time", "titleSlug": "minimum-cost-to-set-cooking-time", "content": "
A generic microwave supports cooking times for:
\n\n1
second.99
minutes and 99
seconds.To set the cooking time, you push at most four digits. The microwave normalizes what you push as four digits by prepending zeroes. It interprets the first two digits as the minutes and the last two digits as the seconds. It then adds them up as the cooking time. For example,
\n\n9
5
4
(three digits). It is normalized as 0954
and interpreted as 9
minutes and 54
seconds.0
0
0
8
(four digits). It is interpreted as 0
minutes and 8
seconds.8
0
9
0
. It is interpreted as 80
minutes and 90
seconds.8
1
3
0
. It is interpreted as 81
minutes and 30
seconds.You are given integers startAt
, moveCost
, pushCost
, and targetSeconds
. Initially, your finger is on the digit startAt
. Moving the finger above any specific digit costs moveCost
units of fatigue. Pushing the digit below the finger once costs pushCost
units of fatigue.
There can be multiple ways to set the microwave to cook for targetSeconds
seconds but you are interested in the way with the minimum cost.
Return the minimum cost to set targetSeconds
seconds of cooking time.
Remember that one minute consists of 60
seconds.
\n
Example 1:
\n\n\nInput: startAt = 1, moveCost = 2, pushCost = 1, targetSeconds = 600\nOutput: 6\nExplanation: The following are the possible ways to set the cooking time.\n- 1 0 0 0, interpreted as 10 minutes and 0 seconds.\n The finger is already on digit 1, pushes 1 (with cost 1), moves to 0 (with cost 2), pushes 0 (with cost 1), pushes 0 (with cost 1), and pushes 0 (with cost 1).\n The cost is: 1 + 2 + 1 + 1 + 1 = 6. This is the minimum cost.\n- 0 9 6 0, interpreted as 9 minutes and 60 seconds. That is also 600 seconds.\n The finger moves to 0 (with cost 2), pushes 0 (with cost 1), moves to 9 (with cost 2), pushes 9 (with cost 1), moves to 6 (with cost 2), pushes 6 (with cost 1), moves to 0 (with cost 2), and pushes 0 (with cost 1).\n The cost is: 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 = 12.\n- 9 6 0, normalized as 0960 and interpreted as 9 minutes and 60 seconds.\n The finger moves to 9 (with cost 2), pushes 9 (with cost 1), moves to 6 (with cost 2), pushes 6 (with cost 1), moves to 0 (with cost 2), and pushes 0 (with cost 1).\n The cost is: 2 + 1 + 2 + 1 + 2 + 1 = 9.\n\n\n
Example 2:
\n\n\nInput: startAt = 0, moveCost = 1, pushCost = 2, targetSeconds = 76\nOutput: 6\nExplanation: The optimal way is to push two digits: 7 6, interpreted as 76 seconds.\nThe finger moves to 7 (with cost 1), pushes 7 (with cost 2), moves to 6 (with cost 1), and pushes 6 (with cost 2). The total cost is: 1 + 2 + 1 + 2 = 6\nNote other possible ways are 0076, 076, 0116, and 116, but none of them produces the minimum cost.\n\n\n
\n
Constraints:
\n\n0 <= startAt <= 9
1 <= moveCost, pushCost <= 105
1 <= targetSeconds <= 6039
常见的微波炉可以设置加热时间,且加热时间满足以下条件:
\n\n1
秒钟。99
分 99
秒。你可以 最多 输入 4 个数字 来设置加热时间。如果你输入的位数不足 4 位,微波炉会自动加 前缀 0 来补足 4 位。微波炉会将设置好的四位数中,前 两位当作分钟数,后 两位当作秒数。它们所表示的总时间就是加热时间。比方说:
\n\n9
5
4
(三个数字),被自动补足为 0954
,并表示 9
分 54
秒。0
0
0
8
(四个数字),表示 0
分 8
秒。8
0
9
0
,表示 80
分 90
秒。8
1
3
0
,表示 81
分 30
秒。给你整数 startAt
,moveCost
,pushCost
和 targetSeconds
。一开始,你的手指在数字 startAt
处。将手指移到 任何其他数字 ,需要花费 moveCost
的单位代价。每 输入你手指所在位置的数字一次,需要花费 pushCost
的单位代价。
要设置 targetSeconds
秒的加热时间,可能会有多种设置方法。你想要知道这些方法中,总代价最小为多少。
请你能返回设置 targetSeconds
秒钟加热时间需要花费的最少代价。
请记住,虽然微波炉的秒数最多可以设置到 99
秒,但一分钟等于 60
秒。
\n\n
示例 1:
\n\n\n\n输入:startAt = 1, moveCost = 2, pushCost = 1, targetSeconds = 600\n输出:6\n解释:以下为设置加热时间的所有方法。\n- 1 0 0 0 ,表示 10 分 0 秒。\n 手指一开始就在数字 1 处,输入 1 (代价为 1),移到 0 处(代价为 2),输入 0(代价为 1),输入 0(代价为 1),输入 0(代价为 1)。\n 总代价为:1 + 2 + 1 + 1 + 1 = 6 。这是所有方案中的最小代价。\n- 0 9 6 0,表示 9 分 60 秒。它也表示 600 秒。\n 手指移到 0 处(代价为 2),输入 0 (代价为 1),移到 9 处(代价为 2),输入 9(代价为 1),移到 6 处(代价为 2),输入 6(代价为 1),移到 0 处(代价为 2),输入 0(代价为 1)。\n 总代价为:2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 = 12 。\n- 9 6 0,微波炉自动补全为 0960 ,表示 9 分 60 秒。\n 手指移到 9 处(代价为 2),输入 9 (代价为 1),移到 6 处(代价为 2),输入 6(代价为 1),移到 0 处(代价为 2),输入 0(代价为 1)。\n 总代价为:2 + 1 + 2 + 1 + 2 + 1 = 9 。\n\n\n
示例 2:
\n\n\n\n输入:startAt = 0, moveCost = 1, pushCost = 2, targetSeconds = 76\n输出:6\n解释:最优方案为输入两个数字 7 6,表示 76 秒。\n手指移到 7 处(代价为 1),输入 7 (代价为 2),移到 6 处(代价为 1),输入 6(代价为 2)。总代价为:1 + 2 + 1 + 2 = 6\n其他可行方案为 0076 ,076 ,0116 和 116 ,但是它们的代价都比 6 大。\n\n\n
\n\n
提示:
\n\n0 <= startAt <= 9
1 <= moveCost, pushCost <= 105
1 <= targetSeconds <= 6039
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