{ "data": { "question": { "questionId": "2342", "questionFrontendId": "2256", "categoryTitle": "Algorithms", "boundTopicId": 1456498, "title": "Minimum Average Difference", "titleSlug": "minimum-average-difference", "content": "

You are given a 0-indexed integer array nums of length n.

\n\n

The average difference of the index i is the absolute difference between the average of the first i + 1 elements of nums and the average of the last n - i - 1 elements. Both averages should be rounded down to the nearest integer.

\n\n

Return the index with the minimum average difference. If there are multiple such indices, return the smallest one.

\n\n

Note:

\n\n\n\n

 

\n

Example 1:

\n\n
\nInput: nums = [2,5,3,9,5,3]\nOutput: 3\nExplanation:\n- The average difference of index 0 is: |2 / 1 - (5 + 3 + 9 + 5 + 3) / 5| = |2 / 1 - 25 / 5| = |2 - 5| = 3.\n- The average difference of index 1 is: |(2 + 5) / 2 - (3 + 9 + 5 + 3) / 4| = |7 / 2 - 20 / 4| = |3 - 5| = 2.\n- The average difference of index 2 is: |(2 + 5 + 3) / 3 - (9 + 5 + 3) / 3| = |10 / 3 - 17 / 3| = |3 - 5| = 2.\n- The average difference of index 3 is: |(2 + 5 + 3 + 9) / 4 - (5 + 3) / 2| = |19 / 4 - 8 / 2| = |4 - 4| = 0.\n- The average difference of index 4 is: |(2 + 5 + 3 + 9 + 5) / 5 - 3 / 1| = |24 / 5 - 3 / 1| = |4 - 3| = 1.\n- The average difference of index 5 is: |(2 + 5 + 3 + 9 + 5 + 3) / 6 - 0| = |27 / 6 - 0| = |4 - 0| = 4.\nThe average difference of index 3 is the minimum average difference so return 3.\n
\n\n

Example 2:

\n\n
\nInput: nums = [0]\nOutput: 0\nExplanation:\nThe only index is 0 so return 0.\nThe average difference of index 0 is: |0 / 1 - 0| = |0 - 0| = 0.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "最小平均差", "translatedContent": "

给你一个下标从 0 开始长度为 n 的整数数组 nums 。

\n\n

下标 i 处的 平均差 指的是 nums 中 前 i + 1 个元素平均值和 后 n - i - 1 个元素平均值的 绝对差 。两个平均值都需要 向下取整 到最近的整数。

\n\n

请你返回产生 最小平均差 的下标。如果有多个下标最小平均差相等，请你返回 最小 的一个下标。

\n\n

注意：

\n\n\n\n

 

\n\n

示例 1：

\n\n
输入：nums = [2,5,3,9,5,3]\n输出：3\n解释：\n- 下标 0 处的平均差为：|2 / 1 - (5 + 3 + 9 + 5 + 3) / 5| = |2 / 1 - 25 / 5| = |2 - 5| = 3 。\n- 下标 1 处的平均差为：|(2 + 5) / 2 - (3 + 9 + 5 + 3) / 4| = |7 / 2 - 20 / 4| = |3 - 5| = 2 。\n- 下标 2 处的平均差为：|(2 + 5 + 3) / 3 - (9 + 5 + 3) / 3| = |10 / 3 - 17 / 3| = |3 - 5| = 2 。\n- 下标 3 处的平均差为：|(2 + 5 + 3 + 9) / 4 - (5 + 3) / 2| = |19 / 4 - 8 / 2| = |4 - 4| = 0 。 \n- 下标 4 处的平均差为：|(2 + 5 + 3 + 9 + 5) / 5 - 3 / 1| = |24 / 5 - 3 / 1| = |4 - 3| = 1 。\n- 下标 5 处的平均差为：|(2 + 5 + 3 + 9 + 5 + 3) / 6 - 0| = |27 / 6 - 0| = |4 - 0| = 4 。\n下标 3 处的平均差为最小平均差，所以返回 3 。\n
\n\n

示例 2：

\n\n
输入：nums = [0]\n输出：0\n解释：\n唯一的下标是 0 ，所以我们返回 0 。\n下标 0 处的平均差为：|0 / 1 - 0| = |0 - 0| = 0 。\n
\n\n

 

\n\n

提示：

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