{ "data": { "question": { "questionId": "2466", "questionFrontendId": "2382", "categoryTitle": "Algorithms", "boundTopicId": 1759859, "title": "Maximum Segment Sum After Removals", "titleSlug": "maximum-segment-sum-after-removals", "content": "

You are given two 0-indexed integer arrays nums and removeQueries, both of length n. For the ith query, the element in nums at the index removeQueries[i] is removed, splitting nums into different segments.

\n\n

A segment is a contiguous sequence of positive integers in nums. A segment sum is the sum of every element in a segment.

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Return an integer array answer, of length n, where answer[i] is the maximum segment sum after applying the ith removal.

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Note: The same index will not be removed more than once.

\n\n

 

\n

Example 1:

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\nInput: nums = [1,2,5,6,1], removeQueries = [0,3,2,4,1]\nOutput: [14,7,2,2,0]\nExplanation: Using 0 to indicate a removed element, the answer is as follows:\nQuery 1: Remove the 0th element, nums becomes [0,2,5,6,1] and the maximum segment sum is 14 for segment [2,5,6,1].\nQuery 2: Remove the 3rd element, nums becomes [0,2,5,0,1] and the maximum segment sum is 7 for segment [2,5].\nQuery 3: Remove the 2nd element, nums becomes [0,2,0,0,1] and the maximum segment sum is 2 for segment [2]. \nQuery 4: Remove the 4th element, nums becomes [0,2,0,0,0] and the maximum segment sum is 2 for segment [2]. \nQuery 5: Remove the 1st element, nums becomes [0,0,0,0,0] and the maximum segment sum is 0, since there are no segments.\nFinally, we return [14,7,2,2,0].
\n\n

Example 2:

\n\n
\nInput: nums = [3,2,11,1], removeQueries = [3,2,1,0]\nOutput: [16,5,3,0]\nExplanation: Using 0 to indicate a removed element, the answer is as follows:\nQuery 1: Remove the 3rd element, nums becomes [3,2,11,0] and the maximum segment sum is 16 for segment [3,2,11].\nQuery 2: Remove the 2nd element, nums becomes [3,2,0,0] and the maximum segment sum is 5 for segment [3,2].\nQuery 3: Remove the 1st element, nums becomes [3,0,0,0] and the maximum segment sum is 3 for segment [3].\nQuery 4: Remove the 0th element, nums becomes [0,0,0,0] and the maximum segment sum is 0, since there are no segments.\nFinally, we return [16,5,3,0].\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "删除操作后的最大子段和", "translatedContent": "

给你两个下标从 0 开始的整数数组 nums 和 removeQueries ，两者长度都为 n 。对于第 i 个查询，nums 中位于下标 removeQueries[i] 处的元素被删除，将 nums 分割成更小的子段。

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一个 子段 是 nums 中连续 正 整数形成的序列。子段和 是子段中所有元素的和。

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请你返回一个长度为 n 的整数数组 answer ，其中 answer[i]是第 i 次删除操作以后的 最大 子段和。

\n\n

注意：一个下标至多只会被删除一次。

\n\n

 

\n\n

示例 1：

\n\n
输入：nums = [1,2,5,6,1], removeQueries = [0,3,2,4,1]\n输出：[14,7,2,2,0]\n解释：用 0 表示被删除的元素，答案如下所示：\n查询 1 ：删除第 0 个元素，nums 变成 [0,2,5,6,1] ，最大子段和为子段 [2,5,6,1] 的和 14 。\n查询 2 ：删除第 3 个元素，nums 变成 [0,2,5,0,1] ，最大子段和为子段 [2,5] 的和 7 。\n查询 3 ：删除第 2 个元素，nums 变成 [0,2,0,0,1] ，最大子段和为子段 [2] 的和 2 。\n查询 4 ：删除第 4 个元素，nums 变成 [0,2,0,0,0] ，最大子段和为子段 [2] 的和 2 。\n查询 5 ：删除第 1 个元素，nums 变成 [0,0,0,0,0] ，最大子段和为 0 ，因为没有任何子段存在。\n所以，我们返回 [14,7,2,2,0] 。
\n\n

示例 2：

\n\n
输入：nums = [3,2,11,1], removeQueries = [3,2,1,0]\n输出：[16,5,3,0]\n解释：用 0 表示被删除的元素，答案如下所示：\n查询 1 ：删除第 3 个元素，nums 变成 [3,2,11,0] ，最大子段和为子段 [3,2,11] 的和 16 。\n查询 2 ：删除第 2 个元素，nums 变成 [3,2,0,0] ，最大子段和为子段 [3,2] 的和 5 。\n查询 3 ：删除第 1 个元素，nums 变成 [3,0,0,0] ，最大子段和为子段 [3] 的和 3 。\n查询 5 ：删除第 0 个元素，nums 变成 [0,0,0,0] ，最大子段和为 0 ，因为没有任何子段存在。\n所以，我们返回 [16,5,3,0] 。\n
\n\n

 

\n\n

提示：

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