{ "data": { "question": { "questionId": "2482", "questionFrontendId": "2397", "categoryTitle": "Algorithms", "boundTopicId": 1793232, "title": "Maximum Rows Covered by Columns", "titleSlug": "maximum-rows-covered-by-columns", "content": "
You are given a 0-indexed m x n
binary matrix matrix
and an integer numSelect
, which denotes the number of distinct columns you must select from matrix
.
Let us consider s = {c1, c2, ...., cnumSelect}
as the set of columns selected by you. A row row
is covered by s
if:
matrix[row][col]
(0 <= col <= n - 1
) where matrix[row][col] == 1
, col
is present in s
or,row
has a value of 1
.You need to choose numSelect
columns such that the number of rows that are covered is maximized.
Return the maximum number of rows that can be covered by a set of numSelect
columns.
\n
Example 1:
\n\n\nInput: matrix = [[0,0,0],[1,0,1],[0,1,1],[0,0,1]], numSelect = 2\nOutput: 3\nExplanation: One possible way to cover 3 rows is shown in the diagram above.\nWe choose s = {0, 2}.\n- Row 0 is covered because it has no occurrences of 1.\n- Row 1 is covered because the columns with value 1, i.e. 0 and 2 are present in s.\n- Row 2 is not covered because matrix[2][1] == 1 but 1 is not present in s.\n- Row 3 is covered because matrix[2][2] == 1 and 2 is present in s.\nThus, we can cover three rows.\nNote that s = {1, 2} will also cover 3 rows, but it can be shown that no more than three rows can be covered.\n\n\n
Example 2:
\n\n\nInput: matrix = [[1],[0]], numSelect = 1\nOutput: 2\nExplanation: Selecting the only column will result in both rows being covered since the entire matrix is selected.\nTherefore, we return 2.\n\n\n
\n
Constraints:
\n\nm == matrix.length
n == matrix[i].length
1 <= m, n <= 12
matrix[i][j]
is either 0
or 1
.1 <= numSelect <= n
给你一个下标从 0 开始、大小为 m x n
的二进制矩阵 matrix
;另给你一个整数 numSelect
,表示你必须从 matrix
中选择的 不同 列的数量。
如果一行中所有的 1
都被你选中的列所覆盖,则认为这一行被 覆盖 了。
形式上,假设 s = {c1, c2, ...., cnumSelect}
是你选择的列的集合。对于矩阵中的某一行 row
,如果满足下述条件,则认为这一行被集合 s
覆盖:
matrix[row][col] == 1
的每个单元格 matrix[row][col]
(0 <= col <= n - 1
),col
均存在于 s
中,或者row
中 不存在 值为 1
的单元格。你需要从矩阵中选出 numSelect
个列,使集合覆盖的行数最大化。
返回一个整数,表示可以由 numSelect
列构成的集合 覆盖 的 最大行数 。
\n\n
示例 1:
\n\n\n\n
\n输入:matrix = [[0,0,0],[1,0,1],[0,1,1],[0,0,1]], numSelect = 2\n输出:3\n解释:\n图示中显示了一种覆盖 3 行的可行办法。\n选择 s = {0, 2} 。\n- 第 0 行被覆盖,因为其中没有出现 1 。\n- 第 1 行被覆盖,因为值为 1 的两列(即 0 和 2)均存在于 s 中。\n- 第 2 行未被覆盖,因为 matrix[2][1] == 1 但是 1 未存在于 s 中。\n- 第 3 行被覆盖,因为 matrix[2][2] == 1 且 2 存在于 s 中。\n因此,可以覆盖 3 行。\n另外 s = {1, 2} 也可以覆盖 3 行,但可以证明无法覆盖更多行。\n\n
示例 2:
\n\n\n\n
\n输入:matrix = [[1],[0]], numSelect = 1\n输出:2\n解释:\n选择唯一的一列,两行都被覆盖了,因为整个矩阵都被覆盖了。\n所以我们返回 2 。\n\n\n
\n\n
提示:
\n\nm == matrix.length
n == matrix[i].length
1 <= m, n <= 12
matrix[i][j]
要么是 0
要么是 1
1 <= numSelect <= n
cols
columns.",
"For each valid set, check how many rows are covered, and return the maximum."
],
"solution": null,
"status": null,
"sampleTestCase": "[[0,0,0],[1,0,1],[0,1,1],[0,0,1]]\n2",
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