You are given an integer array nums of size n.
Consider a non-empty subarray from nums that has the maximum possible bitwise AND.
k be the maximum value of the bitwise AND of any subarray of nums. Then, only subarrays with a bitwise AND equal to k should be considered.Return the length of the longest such subarray.
\n\nThe bitwise AND of an array is the bitwise AND of all the numbers in it.
\n\nA subarray is a contiguous sequence of elements within an array.
\n\n\n
Example 1:
\n\n\nInput: nums = [1,2,3,3,2,2]\nOutput: 2\nExplanation:\nThe maximum possible bitwise AND of a subarray is 3.\nThe longest subarray with that value is [3,3], so we return 2.\n\n\n
Example 2:
\n\n\nInput: nums = [1,2,3,4]\nOutput: 1\nExplanation:\nThe maximum possible bitwise AND of a subarray is 4.\nThe longest subarray with that value is [4], so we return 1.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1051 <= nums[i] <= 106给你一个长度为 n 的整数数组 nums 。
考虑 nums 中进行 按位与（bitwise AND）运算得到的值 最大 的 非空 子数组。
k 是 nums 任意 子数组执行按位与运算所能得到的最大值。那么，只需要考虑那些执行一次按位与运算后等于 k 的子数组。返回满足要求的 最长 子数组的长度。
\n\n数组的按位与就是对数组中的所有数字进行按位与运算。
\n\n子数组 是数组中的一个连续元素序列。
\n\n\n\n
示例 1：
\n\n\n输入：nums = [1,2,3,3,2,2]\n输出：2\n解释：\n子数组按位与运算的最大值是 3 。\n能得到此结果的最长子数组是 [3,3]，所以返回 2 。\n\n\n
示例 2：
\n\n\n输入：nums = [1,2,3,4]\n输出：1\n解释：\n子数组按位与运算的最大值是 4 。 \n能得到此结果的最长子数组是 [4]，所以返回 1 。\n\n\n
\n\n
提示：
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