You are given a string s consisting of only lowercase English letters. In one operation, you can do the following:
s, possibly the entire string, then replace each one of its characters with the previous character of the English alphabet. For example, 'b' is converted to 'a', and 'a' is converted to 'z'.Return the lexicographically smallest string you can obtain after performing the above operation exactly once.
\n\nA substring is a contiguous sequence of characters in a string.
\nA stringx is lexicographically smaller than a string y of the same length if x[i] comes before y[i] in alphabetic order for the first position i such that x[i] != y[i].\n\n
Example 1:
\n\n\nInput: s = "cbabc"\nOutput: "baabc"\nExplanation: We apply the operation on the substring starting at index 0, and ending at index 1 inclusive. \nIt can be proven that the resulting string is the lexicographically smallest. \n\n\n
Example 2:
\n\n\nInput: s = "acbbc"\nOutput: "abaab"\nExplanation: We apply the operation on the substring starting at index 1, and ending at index 4 inclusive. \nIt can be proven that the resulting string is the lexicographically smallest. \n\n\n
Example 3:
\n\n\nInput: s = "leetcode"\nOutput: "kddsbncd"\nExplanation: We apply the operation on the entire string. \nIt can be proven that the resulting string is the lexicographically smallest. \n\n\n
\n
Constraints:
\n\n1 <= s.length <= 3 * 105s consists of lowercase English letters给你一个仅由小写英文字母组成的字符串 s 。在一步操作中，你可以完成以下行为：
s 的任一非空子字符串，可能是整个字符串，接着将字符串中的每一个字符替换为英文字母表中的前一个字符。例如，'b' 用 'a' 替换，'a' 用 'z' 替换。返回执行上述操作 恰好一次 后可以获得的 字典序最小 的字符串。
\n\n子字符串 是字符串中的一个连续字符序列。
\n现有长度相同的两个字符串x 和 字符串 y ，在满足 x[i] != y[i] 的第一个位置 i 上，如果 x[i] 在字母表中先于 y[i] 出现，则认为字符串 x 比字符串 y 字典序更小 。\n\n\n\n
示例 1：
\n\n\n输入：s = \"cbabc\"\n输出：\"baabc\"\n解释：我们选择从下标 0 开始、到下标 1 结束的子字符串执行操作。 \n可以证明最终得到的字符串是字典序最小的。\n\n\n
示例 2：
\n\n\n输入：s = \"acbbc\"\n输出：\"abaab\"\n解释：我们选择从下标 1 开始、到下标 4 结束的子字符串执行操作。\n可以证明最终得到的字符串是字典序最小的。\n\n\n
示例 3：
\n\n\n输入：s = \"leetcode\"\n输出：\"kddsbncd\"\n解释：我们选择整个字符串执行操作。\n可以证明最终得到的字符串是字典序最小的。\n\n\n
\n\n
提示：
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collections<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u6ce8\\u610f Python 2.7 \\u5c06\\u57282020\\u5e74\\u540e\\u4e0d\\u518d\\u7ef4\\u62a4<\\/a>\\u3002 \\u5982\\u60f3\\u4f7f\\u7528\\u6700\\u65b0\\u7248\\u7684Python\\uff0c\\u8bf7\\u9009\\u62e9Python 3\\u3002<\\/p>\"],\"c\":[\"C\",\" \\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n 1. 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\\u6a21\\u5757\\u4e2d\\u63d0\\u4f9b\\uff1ahttps:\\/\\/www.rubydoc.info\\/github\\/kanwei\\/algorithms\\/Algorithms<\\/p>\"],\"swift\":[\"Swift\",\" \\u7248\\u672c\\uff1a \\u6211\\u4eec\\u901a\\u5e38\\u4fdd\\u8bc1\\u66f4\\u65b0\\u5230 Apple\\u653e\\u51fa\\u7684\\u6700\\u65b0\\u7248Swift<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u53d1\\u73b0Swift\\u4e0d\\u662f\\u6700\\u65b0\\u7248\\u7684\\uff0c\\u8bf7\\u8054\\u7cfb\\u6211\\u4eec\\uff01\\u6211\\u4eec\\u5c06\\u5c3d\\u5feb\\u66f4\\u65b0\\u3002<\\/p>\"],\"golang\":[\"Go\",\" \\u7248\\u672c\\uff1a \\u652f\\u6301 https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982array<\\/a>, bisect<\\/a>, collections<\\/a>\\u3002 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