{ "data": { "question": { "questionId": "337", "questionFrontendId": "337", "categoryTitle": "Algorithms", "boundTopicId": 1851, "title": "House Robber III", "titleSlug": "house-robber-iii", "content": "
The thief has found himself a new place for his thievery again. There is only one entrance to this area, called root
.
Besides the root
, each house has one and only one parent house. After a tour, the smart thief realized that all houses in this place form a binary tree. It will automatically contact the police if two directly-linked houses were broken into on the same night.
Given the root
of the binary tree, return the maximum amount of money the thief can rob without alerting the police.
\n
Example 1:
\n\n\nInput: root = [3,2,3,null,3,null,1]\nOutput: 7\nExplanation: Maximum amount of money the thief can rob = 3 + 3 + 1 = 7.\n\n\n
Example 2:
\n\n\nInput: root = [3,4,5,1,3,null,1]\nOutput: 9\nExplanation: Maximum amount of money the thief can rob = 4 + 5 = 9.\n\n\n
\n
Constraints:
\n\n[1, 104]
.0 <= Node.val <= 104
小偷又发现了一个新的可行窃的地区。这个地区只有一个入口,我们称之为 root
。
除了 root
之外,每栋房子有且只有一个“父“房子与之相连。一番侦察之后,聪明的小偷意识到“这个地方的所有房屋的排列类似于一棵二叉树”。 如果 两个直接相连的房子在同一天晚上被打劫 ,房屋将自动报警。
给定二叉树的 root
。返回 在不触动警报的情况下 ,小偷能够盗取的最高金额 。
\n\n
示例 1:
\n\n\n\n\n输入: root = [3,2,3,null,3,null,1]\n输出: 7 \n解释: 小偷一晚能够盗取的最高金额 3 + 3 + 1 = 7\n\n
示例 2:
\n\n\n\n\n输入: root = [3,4,5,1,3,null,1]\n输出: 9\n解释: 小偷一晚能够盗取的最高金额 4 + 5 = 9\n\n\n
\n\n
提示:
\n\n\n\n[1, 104]
范围内0 <= Node.val <= 104
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