Given an integer array nums, return the sum of divisors of the integers in that array that have exactly four divisors. If there is no such integer in the array, return 0.
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Example 1:
\n\n\nInput: nums = [21,4,7]\nOutput: 32\nExplanation: \n21 has 4 divisors: 1, 3, 7, 21\n4 has 3 divisors: 1, 2, 4\n7 has 2 divisors: 1, 7\nThe answer is the sum of divisors of 21 only.\n\n\n
Example 2:
\n\n\nInput: nums = [21,21]\nOutput: 64\n\n\n
Example 3:
\n\n\nInput: nums = [1,2,3,4,5]\nOutput: 0\n\n\n
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Constraints:
\n\n1 <= nums.length <= 1041 <= nums[i] <= 105给你一个整数数组 nums，请你返回该数组中恰有四个因数的这些整数的各因数之和。如果数组中不存在满足题意的整数，则返回 0 。
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示例 1：
\n\n\n输入：nums = [21,4,7]\n输出：32\n解释：\n21 有 4 个因数：1, 3, 7, 21\n4 有 3 个因数：1, 2, 4\n7 有 2 个因数：1, 7\n答案仅为 21 的所有因数的和。\n\n\n
示例 2:
\n\n\n输入: nums = [21,21]\n输出: 64\n\n\n
示例 3:
\n\n\n输入: nums = [1,2,3,4,5]\n输出: 0\n\n
\n\n
提示：
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collections<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u6ce8\\u610f Python 2.7 \\u5c06\\u57282020\\u5e74\\u540e\\u4e0d\\u518d\\u7ef4\\u62a4<\\/a>\\u3002 \\u5982\\u60f3\\u4f7f\\u7528\\u6700\\u65b0\\u7248\\u7684Python\\uff0c\\u8bf7\\u9009\\u62e9Python 3\\u3002<\\/p>\"],\"c\":[\"C\",\" \\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n 1. 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