{ "data": { "question": { "questionId": "3181", "questionFrontendId": "2940", "categoryTitle": "Algorithms", "boundTopicId": 2529067, "title": "Find Building Where Alice and Bob Can Meet", "titleSlug": "find-building-where-alice-and-bob-can-meet", "content": "

You are given a 0-indexed array heights of positive integers, where heights[i] represents the height of the ith building.

\n\n

If a person is in building i, they can move to any other building j if and only if i < j and heights[i] < heights[j].

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You are also given another array queries where queries[i] = [ai, bi]. On the ith query, Alice is in building ai while Bob is in building bi.

\n\n

Return an array ans where ans[i] is the index of the leftmost building where Alice and Bob can meet on the ith query. If Alice and Bob cannot move to a common building on query i, set ans[i] to -1.

\n\n

 

\n

Example 1:

\n\n
\nInput: heights = [6,4,8,5,2,7], queries = [[0,1],[0,3],[2,4],[3,4],[2,2]]\nOutput: [2,5,-1,5,2]\nExplanation: In the first query, Alice and Bob can move to building 2 since heights[0] < heights[2] and heights[1] < heights[2]. \nIn the second query, Alice and Bob can move to building 5 since heights[0] < heights[5] and heights[3] < heights[5]. \nIn the third query, Alice cannot meet Bob since Alice cannot move to any other building.\nIn the fourth query, Alice and Bob can move to building 5 since heights[3] < heights[5] and heights[4] < heights[5].\nIn the fifth query, Alice and Bob are already in the same building.  \nFor ans[i] != -1, It can be shown that ans[i] is the leftmost building where Alice and Bob can meet.\nFor ans[i] == -1, It can be shown that there is no building where Alice and Bob can meet.\n
\n\n

Example 2:

\n\n
\nInput: heights = [5,3,8,2,6,1,4,6], queries = [[0,7],[3,5],[5,2],[3,0],[1,6]]\nOutput: [7,6,-1,4,6]\nExplanation: In the first query, Alice can directly move to Bob's building since heights[0] < heights[7].\nIn the second query, Alice and Bob can move to building 6 since heights[3] < heights[6] and heights[5] < heights[6].\nIn the third query, Alice cannot meet Bob since Bob cannot move to any other building.\nIn the fourth query, Alice and Bob can move to building 4 since heights[3] < heights[4] and heights[0] < heights[4].\nIn the fifth query, Alice can directly move to Bob's building since heights[1] < heights[6].\nFor ans[i] != -1, It can be shown that ans[i] is the leftmost building where Alice and Bob can meet.\nFor ans[i] == -1, It can be shown that there is no building where Alice and Bob can meet.\n\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "找到 Alice 和 Bob 可以相遇的建筑", "translatedContent": "

给你一个下标从 0 开始的正整数数组 heights ,其中 heights[i] 表示第 i 栋建筑的高度。

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如果一个人在建筑 i ,且存在 i < j 的建筑 j 满足 heights[i] < heights[j] ,那么这个人可以移动到建筑 j 。

\n\n

给你另外一个数组 queries ,其中 queries[i] = [ai, bi] 。第 i 个查询中,Alice 在建筑 ai ,Bob 在建筑 bi 

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请你能返回一个数组 ans ,其中 ans[i] 是第 i 个查询中,Alice 和 Bob 可以相遇的 最左边的建筑 。如果对于查询 i ,Alice Bob 不能相遇,令 ans[i] 为 -1 。

\n\n

 

\n\n

示例 1:

\n\n
\n输入:heights = [6,4,8,5,2,7], queries = [[0,1],[0,3],[2,4],[3,4],[2,2]]\n输出:[2,5,-1,5,2]\n解释:第一个查询中,Alice 和 Bob 可以移动到建筑 2 ,因为 heights[0] < heights[2] 且 heights[1] < heights[2] 。\n第二个查询中,Alice 和 Bob 可以移动到建筑 5 ,因为 heights[0] < heights[5] 且 heights[3] < heights[5] 。\n第三个查询中,Alice 无法与 Bob 相遇,因为 Alice 不能移动到任何其他建筑。\n第四个查询中,Alice 和 Bob 可以移动到建筑 5 ,因为 heights[3] < heights[5] 且 heights[4] < heights[5] 。\n第五个查询中,Alice 和 Bob 已经在同一栋建筑中。\n对于 ans[i] != -1 ,ans[i] 是 Alice 和 Bob 可以相遇的建筑中最左边建筑的下标。\n对于 ans[i] == -1 ,不存在 Alice 和 Bob 可以相遇的建筑。\n
\n\n

示例 2:

\n\n
\n输入:heights = [5,3,8,2,6,1,4,6], queries = [[0,7],[3,5],[5,2],[3,0],[1,6]]\n输出:[7,6,-1,4,6]\n解释:第一个查询中,Alice 可以直接移动到 Bob 的建筑,因为 heights[0] < heights[7] 。\n第二个查询中,Alice 和 Bob 可以移动到建筑 6 ,因为 heights[3] < heights[6] 且 heights[5] < heights[6] 。\n第三个查询中,Alice 无法与 Bob 相遇,因为 Bob 不能移动到任何其他建筑。\n第四个查询中,Alice 和 Bob 可以移动到建筑 4 ,因为 heights[3] < heights[4] 且 heights[0] < heights[4] 。\n第五个查询中,Alice 可以直接移动到 Bob 的建筑,因为 heights[1] < heights[6] 。\n对于 ans[i] != -1 ,ans[i] 是 Alice 和 Bob 可以相遇的建筑中最左边建筑的下标。\n对于 ans[i] == -1 ,不存在 Alice 和 Bob 可以相遇的建筑。\n
\n\n

 

\n\n

提示:

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leftmostBuildingQueries(self, heights, queries):\n \"\"\"\n :type heights: List[int]\n :type queries: List[List[int]]\n :rtype: List[int]\n \"\"\"", "__typename": "CodeSnippetNode" }, { "lang": "Python3", "langSlug": "python3", "code": "class Solution:\n def leftmostBuildingQueries(self, heights: List[int], queries: List[List[int]]) -> List[int]:", "__typename": "CodeSnippetNode" }, { "lang": "C", "langSlug": "c", "code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* leftmostBuildingQueries(int* heights, int heightsSize, int** queries, int queriesSize, int* queriesColSize, int* returnSize) {\n \n}", "__typename": "CodeSnippetNode" }, { "lang": "C#", "langSlug": "csharp", "code": "public class Solution {\n public int[] LeftmostBuildingQueries(int[] heights, int[][] queries) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "JavaScript", "langSlug": "javascript", "code": "/**\n * @param {number[]} heights\n * @param {number[][]} queries\n * @return {number[]}\n */\nvar leftmostBuildingQueries = function(heights, queries) {\n\n};", "__typename": "CodeSnippetNode" }, { "lang": "TypeScript", "langSlug": "typescript", "code": "function leftmostBuildingQueries(heights: number[], queries: number[][]): number[] {\n \n};", "__typename": "CodeSnippetNode" }, { "lang": "PHP", "langSlug": "php", "code": "class Solution {\n\n /**\n * @param Integer[] $heights\n * @param Integer[][] $queries\n * @return Integer[]\n */\n function leftmostBuildingQueries($heights, $queries) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Swift", "langSlug": "swift", "code": "class Solution {\n func leftmostBuildingQueries(_ heights: [Int], _ queries: [[Int]]) -> [Int] {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Kotlin", "langSlug": "kotlin", "code": "class Solution {\n fun leftmostBuildingQueries(heights: IntArray, queries: Array): IntArray {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Dart", "langSlug": "dart", "code": "class Solution {\n List leftmostBuildingQueries(List heights, List> queries) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Go", "langSlug": "golang", "code": "func leftmostBuildingQueries(heights []int, queries [][]int) []int {\n\n}", "__typename": "CodeSnippetNode" }, { "lang": "Ruby", "langSlug": "ruby", "code": "# @param {Integer[]} heights\n# @param {Integer[][]} queries\n# @return {Integer[]}\ndef leftmost_building_queries(heights, queries)\n\nend", "__typename": "CodeSnippetNode" }, { "lang": "Scala", "langSlug": "scala", "code": "object Solution {\n def leftmostBuildingQueries(heights: Array[Int], queries: Array[Array[Int]]): Array[Int] = {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Rust", "langSlug": "rust", "code": "impl Solution {\n pub fn leftmost_building_queries(heights: Vec, queries: Vec>) -> Vec {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Racket", "langSlug": "racket", "code": "(define/contract (leftmost-building-queries heights queries)\n (-> (listof exact-integer?) (listof (listof exact-integer?)) (listof exact-integer?))\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec leftmost_building_queries(Heights :: [integer()], Queries :: [[integer()]]) -> [integer()].\nleftmost_building_queries(Heights, Queries) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec leftmost_building_queries(heights :: [integer], queries :: [[integer]]) :: [integer]\n def leftmost_building_queries(heights, queries) do\n \n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"2.8K\", \"totalSubmission\": \"6.1K\", \"totalAcceptedRaw\": 2794, \"totalSubmissionRaw\": 6113, \"acRate\": \"45.7%\"}", "hints": [ "For each query [x, y], if x > y, swap x and y. Now, we can assume that x <= y.", "For each query [x, y], if x == y or heights[x] < heights[y], then the answer is y since x ≤ y.", "Otherwise, we need to find the smallest index t such that y < t and heights[x] < heights[t]. Note that heights[y] <= heights[x], so heights[x] < heights[t] is a sufficient condition.", "To find index t for each query, sort the queries in descending order of y. Iterate over the queries while maintaining a monotonic stack which we can binary search over to find index t." ], "solution": null, "status": null, "sampleTestCase": "[6,4,8,5,2,7]\n[[0,1],[0,3],[2,4],[3,4],[2,2]]", "metaData": "{\n \"name\": \"leftmostBuildingQueries\",\n \"params\": [\n {\n \"name\": \"heights\",\n \"type\": \"integer[]\"\n },\n {\n \"type\": \"integer[][]\",\n \"name\": \"queries\"\n }\n ],\n \"return\": {\n \"type\": \"integer[]\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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