{ "data": { "question": { "questionId": "1547", "questionFrontendId": "1436", "categoryTitle": "Algorithms", "boundTopicId": 225379, "title": "Destination City", "titleSlug": "destination-city", "content": "
You are given the array paths
, where paths[i] = [cityAi, cityBi]
means there exists a direct path going from cityAi
to cityBi
. Return the destination city, that is, the city without any path outgoing to another city.
It is guaranteed that the graph of paths forms a line without any loop, therefore, there will be exactly one destination city.
\n\n\n
Example 1:
\n\n\nInput: paths = [["London","New York"],["New York","Lima"],["Lima","Sao Paulo"]]\nOutput: "Sao Paulo" \nExplanation: Starting at "London" city you will reach "Sao Paulo" city which is the destination city. Your trip consist of: "London" -> "New York" -> "Lima" -> "Sao Paulo".\n\n\n
Example 2:
\n\n\nInput: paths = [["B","C"],["D","B"],["C","A"]]\nOutput: "A"\nExplanation: All possible trips are: \n"D" -> "B" -> "C" -> "A". \n"B" -> "C" -> "A". \n"C" -> "A". \n"A". \nClearly the destination city is "A".\n\n\n
Example 3:
\n\n\nInput: paths = [["A","Z"]]\nOutput: "Z"\n\n\n
\n
Constraints:
\n\n1 <= paths.length <= 100
paths[i].length == 2
1 <= cityAi.length, cityBi.length <= 10
cityAi != cityBi
给你一份旅游线路图,该线路图中的旅行线路用数组 paths
表示,其中 paths[i] = [cityAi, cityBi]
表示该线路将会从 cityAi
直接前往 cityBi
。请你找出这次旅行的终点站,即没有任何可以通往其他城市的线路的城市。
题目数据保证线路图会形成一条不存在循环的线路,因此恰有一个旅行终点站。
\n\n\n\n
示例 1:
\n\n\n输入:paths = [[\"London\",\"New York\"],[\"New York\",\"Lima\"],[\"Lima\",\"Sao Paulo\"]]\n输出:\"Sao Paulo\" \n解释:从 \"London\" 出发,最后抵达终点站 \"Sao Paulo\" 。本次旅行的路线是 \"London\" -> \"New York\" -> \"Lima\" -> \"Sao Paulo\" 。\n\n\n
示例 2:
\n\n\n输入:paths = [[\"B\",\"C\"],[\"D\",\"B\"],[\"C\",\"A\"]]\n输出:\"A\"\n解释:所有可能的线路是:\n\"D\" -> \"B\" -> \"C\" -> \"A\". \n\"B\" -> \"C\" -> \"A\". \n\"C\" -> \"A\". \n\"A\". \n显然,旅行终点站是 \"A\" 。\n\n\n
示例 3:
\n\n\n输入:paths = [[\"A\",\"Z\"]]\n输出:\"Z\"\n\n\n
\n\n
提示:
\n\n1 <= paths.length <= 100
paths[i].length == 2
1 <= cityAi.length, cityBi.length <= 10
cityAi != cityBi
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