{ "data": { "question": { "questionId": "807", "questionFrontendId": "791", "categoryTitle": "Algorithms", "boundTopicId": 1611, "title": "Custom Sort String", "titleSlug": "custom-sort-string", "content": "

You are given two strings order and s. All the characters of order are unique and were sorted in some custom order previously.

\n\n

Permute the characters of s so that they match the order that order was sorted. More specifically, if a character x occurs before a character y in order, then x should occur before y in the permuted string.

\n\n

Return any permutation of s that satisfies this property.

\n\n

 

\n

Example 1:

\n\n
\nInput: order = "cba", s = "abcd"\nOutput: "cbad"\nExplanation: \n"a", "b", "c" appear in order, so the order of "a", "b", "c" should be "c", "b", and "a". \nSince "d" does not appear in order, it can be at any position in the returned string. "dcba", "cdba", "cbda" are also valid outputs.\n
\n\n

Example 2:

\n\n
\nInput: order = "cbafg", s = "abcd"\nOutput: "cbad"\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "自定义字符串排序", "translatedContent": "

给定两个字符串 ordersorder 的所有字母都是 唯一 的,并且以前按照一些自定义的顺序排序。

\n\n

s 的字符进行置换,使其与排序的 order 相匹配。更具体地说,如果在 order 中的字符 x 出现字符 y 之前,那么在排列后的字符串中, x 也应该出现在 y 之前。

\n\n

返回 满足这个性质的 s 的任意一种排列 

\n\n

 

\n\n

示例 1:

\n\n
\n输入: order = \"cba\", s = \"abcd\"\n输出: \"cbad\"\n解释: \n“a”、“b”、“c”是按顺序出现的,所以“a”、“b”、“c”的顺序应该是“c”、“b”、“a”。\n因为“d”不是按顺序出现的,所以它可以在返回的字符串中的任何位置。“dcba”、“cdba”、“cbda”也是有效的输出。
\n\n

示例 2:

\n\n
\n输入: order = \"cbafg\", s = \"abcd\"\n输出: \"cbad\"\n
\n\n

 

\n\n

提示:

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