You would like to make dessert and are preparing to buy the ingredients. You have n ice cream base flavors and m types of toppings to choose from. You must follow these rules when making your dessert:
You are given three inputs:
\n\nbaseCosts, an integer array of length n, where each baseCosts[i] represents the price of the ith ice cream base flavor.toppingCosts, an integer array of length m, where each toppingCosts[i] is the price of one of the ith topping.target, an integer representing your target price for dessert.You want to make a dessert with a total cost as close to target as possible.
Return the closest possible cost of the dessert to target. If there are multiple, return the lower one.
\n
Example 1:
\n\n\nInput: baseCosts = [1,7], toppingCosts = [3,4], target = 10\nOutput: 10\nExplanation: Consider the following combination (all 0-indexed):\n- Choose base 1: cost 7\n- Take 1 of topping 0: cost 1 x 3 = 3\n- Take 0 of topping 1: cost 0 x 4 = 0\nTotal: 7 + 3 + 0 = 10.\n\n\n
Example 2:
\n\n\nInput: baseCosts = [2,3], toppingCosts = [4,5,100], target = 18\nOutput: 17\nExplanation: Consider the following combination (all 0-indexed):\n- Choose base 1: cost 3\n- Take 1 of topping 0: cost 1 x 4 = 4\n- Take 2 of topping 1: cost 2 x 5 = 10\n- Take 0 of topping 2: cost 0 x 100 = 0\nTotal: 3 + 4 + 10 + 0 = 17. You cannot make a dessert with a total cost of 18.\n\n\n
Example 3:
\n\n\nInput: baseCosts = [3,10], toppingCosts = [2,5], target = 9\nOutput: 8\nExplanation: It is possible to make desserts with cost 8 and 10. Return 8 as it is the lower cost.\n\n\n
\n
Constraints:
\n\nn == baseCosts.lengthm == toppingCosts.length1 <= n, m <= 101 <= baseCosts[i], toppingCosts[i] <= 1041 <= target <= 104你打算做甜点，现在需要购买配料。目前共有 n 种冰激凌基料和 m 种配料可供选购。而制作甜点需要遵循以下几条规则：
给你以下三个输入：
\n\nbaseCosts ，一个长度为 n 的整数数组，其中每个 baseCosts[i] 表示第 i 种冰激凌基料的价格。toppingCosts，一个长度为 m 的整数数组，其中每个 toppingCosts[i] 表示 一份 第 i 种冰激凌配料的价格。target ，一个整数，表示你制作甜点的目标价格。你希望自己做的甜点总成本尽可能接近目标价格 target 。
返回最接近 target 的甜点成本。如果有多种方案，返回 成本相对较低 的一种。
\n\n
示例 1：
\n\n\n输入：baseCosts = [1,7], toppingCosts = [3,4], target = 10\n输出：10\n解释：考虑下面的方案组合（所有下标均从 0 开始）：\n- 选择 1 号基料：成本 7\n- 选择 1 份 0 号配料：成本 1 x 3 = 3\n- 选择 0 份 1 号配料：成本 0 x 4 = 0\n总成本：7 + 3 + 0 = 10 。\n\n\n
示例 2：
\n\n\n输入：baseCosts = [2,3], toppingCosts = [4,5,100], target = 18\n输出：17\n解释：考虑下面的方案组合（所有下标均从 0 开始）：\n- 选择 1 号基料：成本 3\n- 选择 1 份 0 号配料：成本 1 x 4 = 4\n- 选择 2 份 1 号配料：成本 2 x 5 = 10\n- 选择 0 份 2 号配料：成本 0 x 100 = 0\n总成本：3 + 4 + 10 + 0 = 17 。不存在总成本为 18 的甜点制作方案。\n\n\n
示例 3：
\n\n\n输入：baseCosts = [3,10], toppingCosts = [2,5], target = 9\n输出：8\n解释：可以制作总成本为 8 和 10 的甜点。返回 8 ，因为这是成本更低的方案。\n\n\n
示例 4：
\n\n\n输入：baseCosts = [10], toppingCosts = [1], target = 1\n输出：10\n解释：注意，你可以选择不添加任何配料，但你必须选择一种基料。\n\n
\n\n
提示：
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