{ "data": { "question": { "questionId": "713", "questionFrontendId": "713", "categoryTitle": "Algorithms", "boundTopicId": 1257, "title": "Subarray Product Less Than K", "titleSlug": "subarray-product-less-than-k", "content": "

Given an array of integers nums and an integer k, return the number of contiguous subarrays where the product of all the elements in the subarray is strictly less than k.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums = [10,5,2,6], k = 100\nOutput: 8\nExplanation: The 8 subarrays that have product less than 100 are:\n[10], [5], [2], [6], [10, 5], [5, 2], [2, 6], [5, 2, 6]\nNote that [10, 5, 2] is not included as the product of 100 is not strictly less than k.\n
\n\n

Example 2:

\n\n
\nInput: nums = [1,2,3], k = 0\nOutput: 0\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "乘积小于K的子数组", "translatedContent": "

给定一个正整数数组 nums和整数 k

\n\n

请找出该数组内乘积小于 k 的连续的子数组的个数。

\n\n

 

\n\n

示例 1:

\n\n
\n输入: nums = [10,5,2,6], k = 100\n输出: 8\n解释: 8个乘积小于100的子数组分别为: [10], [5], [2], [6], [10,5], [5,2], [2,6], [5,2,6]。\n需要注意的是 [10,5,2] 并不是乘积小于100的子数组。\n
\n\n

示例 2:

\n\n
\n输入: nums = [1,2,3], k = 0\n输出: 0
\n\n

 

\n\n

提示: 

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