There are 3n piles of coins of varying size, you and your friends will take piles of coins as follows:
3 piles of coins (not necessarily consecutive).Given an array of integers piles where piles[i] is the number of coins in the ith pile.
Return the maximum number of coins that you can have.
\n\n\n
Example 1:
\n\n\nInput: piles = [2,4,1,2,7,8]\nOutput: 9\nExplanation: Choose the triplet (2, 7, 8), Alice Pick the pile with 8 coins, you the pile with 7 coins and Bob the last one.\nChoose the triplet (1, 2, 4), Alice Pick the pile with 4 coins, you the pile with 2 coins and Bob the last one.\nThe maximum number of coins which you can have are: 7 + 2 = 9.\nOn the other hand if we choose this arrangement (1, 2, 8), (2, 4, 7) you only get 2 + 4 = 6 coins which is not optimal.\n\n\n
Example 2:
\n\n\nInput: piles = [2,4,5]\nOutput: 4\n\n\n
Example 3:
\n\n\nInput: piles = [9,8,7,6,5,1,2,3,4]\nOutput: 18\n\n\n
\n
Constraints:
\n\n3 <= piles.length <= 105piles.length % 3 == 01 <= piles[i] <= 104有 3n 堆数目不一的硬币，你和你的朋友们打算按以下方式分硬币：
\n\n给你一个整数数组 piles ，其中 piles[i] 是第 i 堆中硬币的数目。
返回你可以获得的最大硬币数目。
\n\n\n\n
示例 1：
\n\n输入：piles = [2,4,1,2,7,8]\n输出：9\n解释：选出 (2, 7, 8) ，Alice 取走 8 枚硬币的那堆，你取走 7 枚硬币的那堆，Bob 取走最后一堆。\n选出 (1, 2, 4) , Alice 取走 4 枚硬币的那堆，你取走 2 枚硬币的那堆，Bob 取走最后一堆。\n你可以获得的最大硬币数目：7 + 2 = 9.\n考虑另外一种情况，如果选出的是 (1, 2, 8) 和 (2, 4, 7) ，你就只能得到 2 + 4 = 6 枚硬币，这不是最优解。\n\n\n
示例 2：
\n\n输入：piles = [2,4,5]\n输出：4\n\n\n
示例 3：
\n\n输入：piles = [9,8,7,6,5,1,2,3,4]\n输出：18\n\n\n
\n\n
提示：
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