You are given an integer array nums, an integer array queries, and an integer x.
For each queries[i], you need to find the index of the queries[i]th occurrence of x in the nums array. If there are fewer than queries[i] occurrences of x, the answer should be -1 for that query.
Return an integer array answer containing the answers to all queries.
\n
Example 1:
\n\nInput: nums = [1,3,1,7], queries = [1,3,2,4], x = 1
\n\nOutput: [0,-1,2,-1]
\n\nExplanation:
\n\nnums, so the answer is -1.nums, so the answer is -1.Example 2:
\n\nInput: nums = [1,2,3], queries = [10], x = 5
\n\nOutput: [-1]
\n\nExplanation:
\n\nnums, so the answer is -1.\n
Constraints:
\n\n1 <= nums.length, queries.length <= 1051 <= queries[i] <= 1051 <= nums[i], x <= 104nums and save all the occurrences of each element in the separate arrays."
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