{ "data": { "question": { "questionId": "1298", "questionFrontendId": "1190", "categoryTitle": "Algorithms", "boundTopicId": 26716, "title": "Reverse Substrings Between Each Pair of Parentheses", "titleSlug": "reverse-substrings-between-each-pair-of-parentheses", "content": "

You are given a string s that consists of lower case English letters and brackets.

\n\n

Reverse the strings in each pair of matching parentheses, starting from the innermost one.

\n\n

Your result should not contain any brackets.

\n\n

 

\n

Example 1:

\n\n
\nInput: s = "(abcd)"\nOutput: "dcba"\n
\n\n

Example 2:

\n\n
\nInput: s = "(u(love)i)"\nOutput: "iloveu"\nExplanation: The substring "love" is reversed first, then the whole string is reversed.\n
\n\n

Example 3:

\n\n
\nInput: s = "(ed(et(oc))el)"\nOutput: "leetcode"\nExplanation: First, we reverse the substring "oc", then "etco", and finally, the whole string.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "反转每对括号间的子串", "translatedContent": "

给出一个字符串 s（仅含有小写英文字母和括号）。

\n\n

请你按照从括号内到外的顺序，逐层反转每对匹配括号中的字符串，并返回最终的结果。

\n\n

注意，您的结果中 不应 包含任何括号。

\n\n

 

\n\n

示例 1：

\n\n
\n输入：s = \"(abcd)\"\n输出：\"dcba\"\n
\n\n

示例 2：

\n\n
\n输入：s = \"(u(love)i)\"\n输出：\"iloveu\"\n解释：先反转子字符串 \"love\" ，然后反转整个字符串。
\n\n

示例 3：

\n\n
\n输入：s = \"(ed(et(oc))el)\"\n输出：\"leetcode\"\n解释：先反转子字符串 \"oc\" ，接着反转 \"etco\" ，然后反转整个字符串。
\n\n

示例 4：

\n\n
\n输入：s = \"a(bcdefghijkl(mno)p)q\"\n输出：\"apmnolkjihgfedcbq\"\n
\n\n

 

\n\n

提示：

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