{ "data": { "question": { "questionId": "1255", "questionFrontendId": "1330", "categoryTitle": "Algorithms", "boundTopicId": 79268, "title": "Reverse Subarray To Maximize Array Value", "titleSlug": "reverse-subarray-to-maximize-array-value", "content": "

You are given an integer array nums. The value of this array is defined as the sum of |nums[i] - nums[i + 1]| for all 0 <= i < nums.length - 1.

\n\n

You are allowed to select any subarray of the given array and reverse it. You can perform this operation only once.

\n\n

Find maximum possible value of the final array.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums = [2,3,1,5,4]\nOutput: 10\nExplanation: By reversing the subarray [3,1,5] the array becomes [2,5,1,3,4] whose value is 10.\n
\n\n

Example 2:

\n\n
\nInput: nums = [2,4,9,24,2,1,10]\nOutput: 68\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "翻转子数组得到最大的数组值", "translatedContent": "

给你一个整数数组 nums 。「数组值」定义为所有满足 0 <= i < nums.length-1 的 |nums[i]-nums[i+1]| 的和。

\n\n

你可以选择给定数组的任意子数组，并将该子数组翻转。但你只能执行这个操作 一次 。

\n\n

请你找到可行的最大 数组值 。

\n\n

 

\n\n

示例 1：

\n\n
输入：nums = [2,3,1,5,4]\n输出：10\n解释：通过翻转子数组 [3,1,5] ，数组变成 [2,5,1,3,4] ，数组值为 10 。\n
\n\n

示例 2：

\n\n
输入：nums = [2,4,9,24,2,1,10]\n输出：68\n
\n\n

 

\n\n

提示：

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