{ "data": { "question": { "questionId": "775", "questionFrontendId": "589", "categoryTitle": "Algorithms", "boundTopicId": 1395, "title": "N-ary Tree Preorder Traversal", "titleSlug": "n-ary-tree-preorder-traversal", "content": "

Given the root of an n-ary tree, return the preorder traversal of its nodes' values.

\n\n

Nary-Tree input serialization is represented in their level order traversal. Each group of children is separated by the null value (See examples)

\n\n

 

\n

Example 1:

\n\n

\n\n
\nInput: root = [1,null,3,2,4,null,5,6]\nOutput: [1,3,5,6,2,4]\n
\n\n

Example 2:

\n\n

\"\"

\n\n
\nInput: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]\nOutput: [1,2,3,6,7,11,14,4,8,12,5,9,13,10]\n
\n\n

 

\n

Constraints:

\n\n\n\n

 

\n

Follow up: Recursive solution is trivial, could you do it iteratively?

\n", "translatedTitle": "N 叉树的前序遍历", "translatedContent": "

给定一个 n 叉树的根节点  root ,返回 其节点值的 前序遍历

\n\n

n 叉树 在输入中按层序遍历进行序列化表示,每组子节点由空值 null 分隔(请参见示例)。

\n\n


\n示例 1:

\n\n

\n\n
\n输入:root = [1,null,3,2,4,null,5,6]\n输出:[1,3,5,6,2,4]\n
\n\n

示例 2:

\n\n

\"\"

\n\n
\n输入:root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]\n输出:[1,2,3,6,7,11,14,4,8,12,5,9,13,10]\n
\n\n

 

\n\n

提示:

\n\n\n\n

 

\n\n

进阶:递归法很简单,你可以使用迭代法完成此题吗?

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"langSlug": "java", "code": "/*\n// Definition for a Node.\nclass Node {\n public int val;\n public List children;\n\n public Node() {}\n\n public Node(int _val) {\n val = _val;\n }\n\n public Node(int _val, List _children) {\n val = _val;\n children = _children;\n }\n};\n*/\n\nclass Solution {\n public List preorder(Node root) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Python", "langSlug": "python", "code": "\"\"\"\n# Definition for a Node.\nclass Node(object):\n def __init__(self, val=None, children=None):\n self.val = val\n self.children = children\n\"\"\"\n\nclass Solution(object):\n def preorder(self, root):\n \"\"\"\n :type root: Node\n :rtype: List[int]\n \"\"\"\n ", "__typename": "CodeSnippetNode" }, { "lang": "Python3", "langSlug": "python3", "code": "\"\"\"\n# Definition for a Node.\nclass Node:\n def __init__(self, val=None, children=None):\n self.val = val\n self.children = children\n\"\"\"\n\nclass Solution:\n def preorder(self, root: 'Node') -> List[int]:\n ", "__typename": "CodeSnippetNode" }, { "lang": "C", "langSlug": "c", "code": "/**\n * Definition for a Node.\n * struct Node {\n * int val;\n * int numChildren;\n * struct Node** children;\n * };\n */\n\n/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* preorder(struct Node* root, int* returnSize) {\n \n}", "__typename": "CodeSnippetNode" }, { "lang": "C#", "langSlug": "csharp", "code": "/*\n// Definition for a Node.\npublic class Node {\n public int val;\n public IList children;\n\n public Node() {}\n\n public Node(int _val) {\n val = _val;\n }\n\n public Node(int _val,IList _children) {\n val = _val;\n children = _children;\n }\n}\n*/\n\npublic class Solution {\n public IList Preorder(Node root) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "JavaScript", "langSlug": "javascript", "code": "/**\n * // Definition for a Node.\n * function Node(val, children) {\n * this.val = val;\n * this.children = children;\n * };\n 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