You are given a 0-indexed array nums consisting of non-negative powers of 2, and an integer target.
In one operation, you must apply the following changes to the array:
\n\nnums[i] such that nums[i] > 1.nums[i] from the array.nums[i] / 2 to the end of nums.Return the minimum number of operations you need to perform so that nums contains a subsequence whose elements sum to target. If it is impossible to obtain such a subsequence, return -1.
A subsequence is an array that can be derived from another array by deleting some or no elements without changing the order of the remaining elements.
\n\n\n
Example 1:
\n\n\nInput: nums = [1,2,8], target = 7\nOutput: 1\nExplanation: In the first operation, we choose element nums[2]. The array becomes equal to nums = [1,2,4,4].\nAt this stage, nums contains the subsequence [1,2,4] which sums up to 7.\nIt can be shown that there is no shorter sequence of operations that results in a subsequnce that sums up to 7.\n\n\n
Example 2:
\n\n\nInput: nums = [1,32,1,2], target = 12\nOutput: 2\nExplanation: In the first operation, we choose element nums[1]. The array becomes equal to nums = [1,1,2,16,16].\nIn the second operation, we choose element nums[3]. The array becomes equal to nums = [1,1,2,16,8,8]\nAt this stage, nums contains the subsequence [1,1,2,8] which sums up to 12.\nIt can be shown that there is no shorter sequence of operations that results in a subsequence that sums up to 12.\n\n
Example 3:
\n\n\nInput: nums = [1,32,1], target = 35\nOutput: -1\nExplanation: It can be shown that no sequence of operations results in a subsequence that sums up to 35.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 10001 <= nums[i] <= 230nums consists only of non-negative powers of two.1 <= target < 231target > sum(nums[i]) , return -1. Otherwise, an answer existstarget, independently, from least significant to most significant bit. bit of target from least to most significant, let X = sum(nums[i]) for nums[i] <= 2^bit.X >= 2^bit, repeatedly select the maximum nums[i] such that nums[i]<=2^bit that has not been selected yet, until the sum of selected elements equals 2^bit. The selected nums[i] will be part of the subsequence whose elements sum to target, so those elements can not be selected again.\r\nnums[i] such that nums[i] > 2^bit, delete nums[i] and add two occurences of nums[i]/2. Without moving to the next bit, go back to the step in hint 3.Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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