You are given a 0-indexed integer array nums. In one operation, you may do the following:
nums that are equal.nums, forming a pair.The operation is done on nums as many times as possible.
Return a 0-indexed integer array answer of size 2 where answer[0] is the number of pairs that are formed and answer[1] is the number of leftover integers in nums after doing the operation as many times as possible.
\n
Example 1:
\n\n\nInput: nums = [1,3,2,1,3,2,2]\nOutput: [3,1]\nExplanation:\nForm a pair with nums[0] and nums[3] and remove them from nums. Now, nums = [3,2,3,2,2].\nForm a pair with nums[0] and nums[2] and remove them from nums. Now, nums = [2,2,2].\nForm a pair with nums[0] and nums[1] and remove them from nums. Now, nums = [2].\nNo more pairs can be formed. A total of 3 pairs have been formed, and there is 1 number leftover in nums.\n\n\n
Example 2:
\n\n\nInput: nums = [1,1]\nOutput: [1,0]\nExplanation: Form a pair with nums[0] and nums[1] and remove them from nums. Now, nums = [].\nNo more pairs can be formed. A total of 1 pair has been formed, and there are 0 numbers leftover in nums.\n\n\n
Example 3:
\n\n\nInput: nums = [0]\nOutput: [0,1]\nExplanation: No pairs can be formed, and there is 1 number leftover in nums.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1000 <= nums[i] <= 100Compiled with clang 11 using the latest C++ 17 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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\\r\\n\\r\\nNote that Python 2.7 will not be maintained past 2020. For the latest Python, please choose Python3 instead.
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Some common data structure implementations are provided in the Algorithms module: https://www.rubydoc.info/github/kanwei/algorithms/Algorithms
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Go 1.17.6.
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