{ "data": { "question": { "questionId": "881", "questionFrontendId": "851", "boundTopicId": null, "title": "Loud and Rich", "titleSlug": "loud-and-rich", "content": "
There is a group of n
people labeled from 0
to n - 1
where each person has a different amount of money and a different level of quietness.
You are given an array richer
where richer[i] = [ai, bi]
indicates that ai
has more money than bi
and an integer array quiet
where quiet[i]
is the quietness of the ith
person. All the given data in richer are logically correct (i.e., the data will not lead you to a situation where x
is richer than y
and y
is richer than x
at the same time).
Return an integer array answer
where answer[x] = y
if y
is the least quiet person (that is, the person y
with the smallest value of quiet[y]
) among all people who definitely have equal to or more money than the person x
.
\n
Example 1:
\n\n\nInput: richer = [[1,0],[2,1],[3,1],[3,7],[4,3],[5,3],[6,3]], quiet = [3,2,5,4,6,1,7,0]\nOutput: [5,5,2,5,4,5,6,7]\nExplanation: \nanswer[0] = 5.\nPerson 5 has more money than 3, which has more money than 1, which has more money than 0.\nThe only person who is quieter (has lower quiet[x]) is person 7, but it is not clear if they have more money than person 0.\nanswer[7] = 7.\nAmong all people that definitely have equal to or more money than person 7 (which could be persons 3, 4, 5, 6, or 7), the person who is the quietest (has lower quiet[x]) is person 7.\nThe other answers can be filled out with similar reasoning.\n\n\n
Example 2:
\n\n\nInput: richer = [], quiet = [0]\nOutput: [0]\n\n\n
\n
Constraints:
\n\nn == quiet.length
1 <= n <= 500
0 <= quiet[i] < n
quiet
are unique.0 <= richer.length <= n * (n - 1) / 2
0 <= ai, bi < n
ai != bi
richer
are unique.richer
are all logically consistent.Compiled with clang 11
using the latest C++ 17 standard.
Your code is compiled with level two optimization (-O2
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Most standard library headers are already included automatically for your convenience.
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