Given an m x n matrix, return a new matrix answer where answer[row][col] is the rank of matrix[row][col].
The rank is an integer that represents how large an element is compared to other elements. It is calculated using the following rules:
\n\n1.p and q are in the same row or column, then:\n\tp < q then rank(p) < rank(q)p == q then rank(p) == rank(q)p > q then rank(p) > rank(q)The test cases are generated so that answer is unique under the given rules.
\n
Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2020/10/18/rank1.jpg\")
\n\nInput: matrix = [[1,2],[3,4]]\nOutput: [[1,2],[2,3]]\nExplanation:\nThe rank of matrix[0][0] is 1 because it is the smallest integer in its row and column.\nThe rank of matrix[0][1] is 2 because matrix[0][1] > matrix[0][0] and matrix[0][0] is rank 1.\nThe rank of matrix[1][0] is 2 because matrix[1][0] > matrix[0][0] and matrix[0][0] is rank 1.\nThe rank of matrix[1][1] is 3 because matrix[1][1] > matrix[0][1], matrix[1][1] > matrix[1][0], and both matrix[0][1] and matrix[1][0] are rank 2.\n\n\n
Example 2:
\n![\"\"](\"https://assets.leetcode.com/uploads/2020/10/18/rank2.jpg\")
\n\nInput: matrix = [[7,7],[7,7]]\nOutput: [[1,1],[1,1]]\n\n\n
Example 3:
\n![\"\"](\"https://assets.leetcode.com/uploads/2020/10/18/rank3.jpg\")
\n\nInput: matrix = [[20,-21,14],[-19,4,19],[22,-47,24],[-19,4,19]]\nOutput: [[4,2,3],[1,3,4],[5,1,6],[1,3,4]]\n\n\n
\n
Constraints:
\n\nm == matrix.lengthn == matrix[i].length1 <= m, n <= 500-109 <= matrix[row][col] <= 109Compiled with clang 11 using the latest C++ 17 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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