You are given an array nums and an integer k. You need to find a subarray of nums such that the absolute difference between k and the bitwise OR of the subarray elements is as small as possible. In other words, select a subarray nums[l..r] such that |k - (nums[l] OR nums[l + 1] ... OR nums[r])| is minimum.
Return the minimum possible value of the absolute difference.
\n\nA subarray is a contiguous non-empty sequence of elements within an array.
\n\n\n
Example 1:
\n\nInput: nums = [1,2,4,5], k = 3
\n\nOutput: 0
\n\nExplanation:
\n\nThe subarray nums[0..1] has OR value 3, which gives the minimum absolute difference |3 - 3| = 0.
Example 2:
\n\nInput: nums = [1,3,1,3], k = 2
\n\nOutput: 1
\n\nExplanation:
\n\nThe subarray nums[1..1] has OR value 3, which gives the minimum absolute difference |3 - 2| = 1.
Example 3:
\n\nInput: nums = [1], k = 10
\n\nOutput: 9
\n\nExplanation:
\n\nThere is a single subarray with OR value 1, which gives the minimum absolute difference |10 - 1| = 9.
\n
Constraints:
\n\n1 <= nums.length <= 1051 <= nums[i] <= 1091 <= k <= 109dp[i] be the set of all the bitwise OR of all the subarrays ending at index i.",
"We start from nums[i], taking the bitwise OR result by including elements one by one from i towards left. Notice that only unset bits can become set on adding an element, and set bits never become unset again.",
"Hence dp[i] can contain at most 30 elements."
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