{ "data": { "question": { "questionId": "807", "questionFrontendId": "791", "categoryTitle": "Algorithms", "boundTopicId": 1611, "title": "Custom Sort String", "titleSlug": "custom-sort-string", "content": "
You are given two strings order
and s
. All the characters of order
are unique and were sorted in some custom order previously.
Permute the characters of s
so that they match the order that order
was sorted. More specifically, if a character x
occurs before a character y
in order
, then x
should occur before y
in the permuted string.
Return any permutation of s
that satisfies this property.
\n
Example 1:
\n\nInput: order = "cba", s = "abcd"
\n\nOutput: "cbad"
\n\nExplanation: "a"
, "b"
, "c"
appear in order, so the order of "a"
, "b"
, "c"
should be "c"
, "b"
, and "a"
.
Since "d"
does not appear in order
, it can be at any position in the returned string. "dcba"
, "cdba"
, "cbda"
are also valid outputs.
Example 2:
\n\nInput: order = "bcafg", s = "abcd"
\n\nOutput: "bcad"
\n\nExplanation: The characters "b"
, "c"
, and "a"
from order
dictate the order for the characters in s
. The character "d"
in s
does not appear in order
, so its position is flexible.
Following the order of appearance in order
, "b"
, "c"
, and "a"
from s
should be arranged as "b"
, "c"
, "a"
. "d"
can be placed at any position since it's not in order. The output "bcad"
correctly follows this rule. Other arrangements like "dbca"
or "bcda"
would also be valid, as long as "b"
, "c"
, "a"
maintain their order.
\n
Constraints:
\n\n1 <= order.length <= 26
1 <= s.length <= 200
order
and s
consist of lowercase English letters.order
are unique.给定两个字符串 order
和 s
。order
的所有字母都是 唯一 的,并且以前按照一些自定义的顺序排序。
对 s
的字符进行置换,使其与排序的 order
相匹配。更具体地说,如果在 order
中的字符 x
出现字符 y
之前,那么在排列后的字符串中, x
也应该出现在 y
之前。
返回 满足这个性质的 s
的任意一种排列 。
\n\n
示例 1:
\n\n\n输入: order = \"cba\", s = \"abcd\"\n输出: \"cbad\"\n解释: \n\"a\"、\"b\"、\"c\"是按顺序出现的,所以\"a\"、\"b\"、\"c\"的顺序应该是\"c\"、\"b\"、\"a\"。\n因为\"d\"不是按顺序出现的,所以它可以在返回的字符串中的任何位置。\"dcba\"、\"cdba\"、\"cbda\"也是有效的输出。\n\n
示例 2:
\n\n\n输入: order = \"cbafg\", s = \"abcd\"\n输出: \"cbad\"\n解释:字符 \"b\"、\"c\" 和 \"a\" 规定了 s 中字符的顺序。s 中的字符 \"d\" 没有在 order 中出现,所以它的位置是弹性的。\n\n按照出现的顺序,s 中的 \"b\"、\"c\"、\"a\" 应排列为\"b\"、\"c\"、\"a\"。\"d\" 可以放在任何位置,因为它没有按顺序排列。输出 \"bcad\" 遵循这一规则。其他排序如 \"dbca\" 或 \"bcda\" 也是有效的,只要维持 \"b\"、\"c\"、\"a\" 的顺序。\n\n\n
\n\n
提示:
\n\n1 <= order.length <= 26
1 <= s.length <= 200
order
和 s
由小写英文字母组成order
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