{ "data": { "question": { "questionId": "3057", "questionFrontendId": "2842", "categoryTitle": "Algorithms", "boundTopicId": 2421034, "title": "Count K-Subsequences of a String With Maximum Beauty", "titleSlug": "count-k-subsequences-of-a-string-with-maximum-beauty", "content": "

You are given a string s and an integer k.

\n\n

A k-subsequence is a subsequence of s, having length k, and all its characters are unique, i.e., every character occurs once.

\n\n

Let f(c) denote the number of times the character c occurs in s.

\n\n

The beauty of a k-subsequence is the sum of f(c) for every character c in the k-subsequence.

\n\n

For example, consider s = "abbbdd" and k = 2:

\n\n\n\n

Return an integer denoting the number of k-subsequences whose beauty is the maximum among all k-subsequences. Since the answer may be too large, return it modulo 109 + 7.

\n\n

A subsequence of a string is a new string formed from the original string by deleting some (possibly none) of the characters without disturbing the relative positions of the remaining characters.

\n\n

Notes

\n\n\n\n

 

\n

Example 1:

\n\n
\nInput: s = "bcca", k = 2\nOutput: 4\nExplanation: From s we have f('a') = 1, f('b') = 1, and f('c') = 2.\nThe k-subsequences of s are: \nbcca having a beauty of f('b') + f('c') = 3 \nbcca having a beauty of f('b') + f('c') = 3 \nbcca having a beauty of f('b') + f('a') = 2 \nbcca having a beauty of f('c') + f('a') = 3\nbcca having a beauty of f('c') + f('a') = 3 \nThere are 4 k-subsequences that have the maximum beauty, 3. \nHence, the answer is 4. \n
\n\n

Example 2:

\n\n
\nInput: s = "abbcd", k = 4\nOutput: 2\nExplanation: From s we have f('a') = 1, f('b') = 2, f('c') = 1, and f('d') = 1. \nThe k-subsequences of s are: \nabbcd having a beauty of f('a') + f('b') + f('c') + f('d') = 5\nabbcd having a beauty of f('a') + f('b') + f('c') + f('d') = 5 \nThere are 2 k-subsequences that have the maximum beauty, 5. \nHence, the answer is 2. \n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "统计一个字符串的 k 子序列美丽值最大的数目", "translatedContent": "

给你一个字符串 s 和一个整数 k 。

\n\n

k 子序列指的是 s 的一个长度为 k 的 子序列 ,且所有字符都是 唯一 的,也就是说每个字符在子序列里只出现过一次。

\n\n

定义 f(c) 为字符 c 在 s 中出现的次数。

\n\n

k 子序列的 美丽值 定义为这个子序列中每一个字符 c 的 f(c) 之  。

\n\n

比方说,s = \"abbbdd\" 和 k = 2 ,我们有:

\n\n\n\n

请你返回一个整数,表示所有 k 子序列 里面 美丽值 是 最大值 的子序列数目。由于答案可能很大,将结果对 109 + 7 取余后返回。

\n\n

一个字符串的子序列指的是从原字符串里面删除一些字符(也可能一个字符也不删除),不改变剩下字符顺序连接得到的新字符串。

\n\n

注意:

\n\n\n\n

 

\n\n

示例 1:

\n\n
\n输入:s = \"bcca\", k = 2\n输出:4\n解释:s 中我们有 f('a') = 1 ,f('b') = 1 和 f('c') = 2 。\ns 的 k 子序列为:\nbcca ,美丽值为 f('b') + f('c') = 3\nbcca ,美丽值为 f('b') + f('c') = 3\nbcca ,美丽值为 f('b') + f('a') = 2\nbcca ,美丽值为 f('c') + f('a') = 3\nbcca ,美丽值为 f('c') + f('a') = 3\n总共有 4 个 k 子序列美丽值为最大值 3 。\n所以答案为 4 。\n
\n\n

示例 2:

\n\n
\n输入:s = \"abbcd\", k = 4\n输出:2\n解释:s 中我们有 f('a') = 1 ,f('b') = 2 ,f('c') = 1 和 f('d') = 1 。\ns 的 k 子序列为:\nabbcd ,美丽值为 f('a') + f('b') + f('c') + f('d') = 5\nabbcd ,美丽值为 f('a') + f('b') + f('c') + f('d') = 5 \n总共有 2 个 k 子序列美丽值为最大值 5 。\n所以答案为 2 。\n
\n\n

 

\n\n

提示:

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exact-integer? exact-integer?)\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec count_k_subsequences_with_max_beauty(S :: unicode:unicode_binary(), K :: integer()) -> integer().\ncount_k_subsequences_with_max_beauty(S, K) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec count_k_subsequences_with_max_beauty(s :: String.t, k :: integer) :: integer\n def count_k_subsequences_with_max_beauty(s, k) do\n \n end\nend", "__typename": "CodeSnippetNode" }, { "lang": "Cangjie", "langSlug": "cangjie", "code": "class Solution {\n func countKSubsequencesWithMaxBeauty(s: String, k: Int64): Int64 {\n\n }\n}", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"3.1K\", \"totalSubmission\": \"10.4K\", \"totalAcceptedRaw\": 3129, \"totalSubmissionRaw\": 10402, \"acRate\": \"30.1%\"}", "hints": [ "Since every character appears once in a k-subsequence, we can solve the following problem first: Find the total number of ways to select k characters such that the sum of their frequencies is maximum.", "An obvious case to eliminate is if k is greater than the number of distinct characters in s, then the answer is 0.", "We are now interested in the top frequencies among the characters. Using a map data structure, let cnt[x] denote the number of characters that have a frequency of x.", "Starting from the maximum value x in cnt. Let i = min(k, cnt[x]) we add to our result cnt[x]Ci * xi representing the number of ways to select i characters from all characters with frequency x, multiplied by the number of ways to choose each individual character. Subtract i from k and continue downwards to the next maximum value.", "Powers, combinations, and additions should be done modulo 109 + 7." ], "solution": null, "status": null, "sampleTestCase": "\"bcca\"\n2", "metaData": "{\n \"name\": \"countKSubsequencesWithMaxBeauty\",\n \"params\": [\n {\n \"name\": \"s\",\n \"type\": \"string\"\n },\n {\n \"type\": \"integer\",\n \"name\": \"k\"\n }\n ],\n \"return\": {\n \"type\": \"integer\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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