{ "data": { "question": { "questionId": "2920", "questionFrontendId": "2808", "categoryTitle": "Algorithms", "boundTopicId": 2372290, "title": "Minimum Seconds to Equalize a Circular Array", "titleSlug": "minimum-seconds-to-equalize-a-circular-array", "content": "

You are given a 0-indexed array nums containing n integers.

\n\n

At each second, you perform the following operation on the array:

\n\n\n\n

Note that all the elements get replaced simultaneously.

\n\n

Return the minimum number of seconds needed to make all elements in the array nums equal.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums = [1,2,1,2]\nOutput: 1\nExplanation: We can equalize the array in 1 second in the following way:\n- At 1st second, replace values at each index with [nums[3],nums[1],nums[3],nums[3]]. After replacement, nums = [2,2,2,2].\nIt can be proven that 1 second is the minimum amount of seconds needed for equalizing the array.\n
\n\n

Example 2:

\n\n
\nInput: nums = [2,1,3,3,2]\nOutput: 2\nExplanation: We can equalize the array in 2 seconds in the following way:\n- At 1st second, replace values at each index with [nums[0],nums[2],nums[2],nums[2],nums[3]]. After replacement, nums = [2,3,3,3,3].\n- At 2nd second, replace values at each index with [nums[1],nums[1],nums[2],nums[3],nums[4]]. After replacement, nums = [3,3,3,3,3].\nIt can be proven that 2 seconds is the minimum amount of seconds needed for equalizing the array.\n
\n\n

Example 3:

\n\n
\nInput: nums = [5,5,5,5]\nOutput: 0\nExplanation: We don't need to perform any operations as all elements in the initial array are the same.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "使循环数组所有元素相等的最少秒数", "translatedContent": "

给你一个下标从 0 开始长度为 n 的数组 nums 。

\n\n

每一秒,你可以对数组执行以下操作:

\n\n\n\n

注意,所有元素会被同时替换。

\n\n

请你返回将数组 nums 中所有元素变成相等元素所需要的 最少 秒数。

\n\n

 

\n\n

示例 1:

\n\n
输入:nums = [1,2,1,2]\n输出:1\n解释:我们可以在 1 秒内将数组变成相等元素:\n- 第 1 秒,将每个位置的元素分别变为 [nums[3],nums[1],nums[3],nums[3]] 。变化后,nums = [2,2,2,2] 。\n1 秒是将数组变成相等元素所需要的最少秒数。\n
\n\n

示例 2:

\n\n
输入:nums = [2,1,3,3,2]\n输出:2\n解释:我们可以在 2 秒内将数组变成相等元素:\n- 第 1 秒,将每个位置的元素分别变为 [nums[0],nums[2],nums[2],nums[2],nums[3]] 。变化后,nums = [2,3,3,3,3] 。\n- 第 2 秒,将每个位置的元素分别变为 [nums[1],nums[1],nums[2],nums[3],nums[4]] 。变化后,nums = [3,3,3,3,3] 。\n2 秒是将数组变成相等元素所需要的最少秒数。\n
\n\n

示例 3:

\n\n
输入:nums = [5,5,5,5]\n输出:0\n解释:不需要执行任何操作,因为一开始数组中的元素已经全部相等。\n
\n\n

 

\n\n

提示:

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