{ "data": { "question": { "questionId": "1881", "questionFrontendId": "1755", "categoryTitle": "Algorithms", "boundTopicId": 591900, "title": "Closest Subsequence Sum", "titleSlug": "closest-subsequence-sum", "content": "

You are given an integer array nums and an integer goal.

\n\n

You want to choose a subsequence of nums such that the sum of its elements is the closest possible to goal. That is, if the sum of the subsequence's elements is sum, then you want to minimize the absolute difference abs(sum - goal).

\n\n

Return the minimum possible value of abs(sum - goal).

\n\n

Note that a subsequence of an array is an array formed by removing some elements (possibly all or none) of the original array.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums = [5,-7,3,5], goal = 6\nOutput: 0\nExplanation: Choose the whole array as a subsequence, with a sum of 6.\nThis is equal to the goal, so the absolute difference is 0.\n
\n\n

Example 2:

\n\n
\nInput: nums = [7,-9,15,-2], goal = -5\nOutput: 1\nExplanation: Choose the subsequence [7,-9,-2], with a sum of -4.\nThe absolute difference is abs(-4 - (-5)) = abs(1) = 1, which is the minimum.\n
\n\n

Example 3:

\n\n
\nInput: nums = [1,2,3], goal = -7\nOutput: 7\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "最接近目标值的子序列和", "translatedContent": "

给你一个整数数组 nums 和一个目标值 goal

\n\n

你需要从 nums 中选出一个子序列,使子序列元素总和最接近 goal 。也就是说,如果子序列元素和为 sum ,你需要 最小化绝对差 abs(sum - goal)

\n\n

返回 abs(sum - goal) 可能的 最小值

\n\n

注意,数组的子序列是通过移除原始数组中的某些元素(可能全部或无)而形成的数组。

\n\n

 

\n\n

示例 1:

\n\n
输入:nums = [5,-7,3,5], goal = 6\n输出:0\n解释:选择整个数组作为选出的子序列,元素和为 6 。\n子序列和与目标值相等,所以绝对差为 0 。\n
\n\n

示例 2:

\n\n
输入:nums = [7,-9,15,-2], goal = -5\n输出:1\n解释:选出子序列 [7,-9,-2] ,元素和为 -4 。\n绝对差为 abs(-4 - (-5)) = abs(1) = 1 ,是可能的最小值。\n
\n\n

示例 3:

\n\n
输入:nums = [1,2,3], goal = -7\n输出:7\n
\n\n

 

\n\n

提示:

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exact-integer?)\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec min_abs_difference(Nums :: [integer()], Goal :: integer()) -> integer().\nmin_abs_difference(Nums, Goal) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec min_abs_difference(nums :: [integer], goal :: integer) :: integer\n def min_abs_difference(nums, goal) do\n \n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"7K\", \"totalSubmission\": \"15K\", \"totalAcceptedRaw\": 6966, \"totalSubmissionRaw\": 15043, \"acRate\": \"46.3%\"}", "hints": [ "The naive solution is to check all possible subsequences. This works in O(2^n).", "Divide the array into two parts of nearly is equal size.", "Consider all subsets of one part and make a list of all possible subset sums and sort this list.", "Consider all subsets of the other part, and for each one, let its sum = x, do binary search to get the nearest possible value to goal - x in the first part." ], "solution": null, "status": null, "sampleTestCase": "[5,-7,3,5]\n6", "metaData": "{\n \"name\": \"minAbsDifference\",\n \"params\": [\n {\n \"name\": \"nums\",\n \"type\": \"integer[]\"\n },\n {\n \"type\": \"integer\",\n \"name\": \"goal\"\n }\n ],\n \"return\": {\n \"type\": \"integer\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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