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"categoryTitle": "Algorithms",
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"title": "Camelcase Matching",
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"content": "<p>Given an array of strings <code>queries</code> and a string <code>pattern</code>, return a boolean array <code>answer</code> where <code>answer[i]</code> is <code>true</code> if <code>queries[i]</code> matches <code>pattern</code>, and <code>false</code> otherwise.</p>\n\n<p>A query word <code>queries[i]</code> matches <code>pattern</code> if you can insert lowercase English letters pattern so that it equals the query. You may insert each character at any position and you may not insert any characters.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FB"\n<strong>Output:</strong> [true,false,true,true,false]\n<strong>Explanation:</strong> "FooBar" can be generated like this "F" + "oo" + "B" + "ar".\n"FootBall" can be generated like this "F" + "oot" + "B" + "all".\n"FrameBuffer" can be generated like this "F" + "rame" + "B" + "uffer".\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBa"\n<strong>Output:</strong> [true,false,true,false,false]\n<strong>Explanation:</strong> "FooBar" can be generated like this "Fo" + "o" + "Ba" + "r".\n"FootBall" can be generated like this "Fo" + "ot" + "Ba" + "ll".\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBaT"\n<strong>Output:</strong> [false,true,false,false,false]\n<strong>Explanation:</strong> "FooBarTest" can be generated like this "Fo" + "o" + "Ba" + "r" + "T" + "est".\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= pattern.length, queries.length <= 100</code></li>\n\t<li><code>1 <= queries[i].length <= 100</code></li>\n\t<li><code>queries[i]</code> and <code>pattern</code> consist of English letters.</li>\n</ul>\n",
"translatedTitle": "驼峰式匹配",
"translatedContent": "<p>给你一个字符串数组 <code>queries</code>，和一个表示模式的字符串 <code>pattern</code>，请你返回一个布尔数组 <code>answer</code> 。只有在待查项 <code>queries[i]</code> 与模式串 <code>pattern</code> 匹配时， <code>answer[i]</code> 才为 <code>true</code>，否则为 <code>false</code>。</p>\n\n<p>如果可以将<strong>小写字母</strong>插入模式串 <code>pattern</code> 得到待查询项 <code>query</code>，那么待查询项与给定模式串匹配。可以在任何位置插入每个字符，也可以不插入字符。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>queries = [\"FooBar\",\"FooBarTest\",\"FootBall\",\"FrameBuffer\",\"ForceFeedBack\"], pattern = \"FB\"\n<strong>输出：</strong>[true,false,true,true,false]\n<strong>示例：</strong>\n\"FooBar\" 可以这样生成：\"F\" + \"oo\" + \"B\" + \"ar\"。\n\"FootBall\" 可以这样生成：\"F\" + \"oot\" + \"B\" + \"all\".\n\"FrameBuffer\" 可以这样生成：\"F\" + \"rame\" + \"B\" + \"uffer\".</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>queries = [\"FooBar\",\"FooBarTest\",\"FootBall\",\"FrameBuffer\",\"ForceFeedBack\"], pattern = \"FoBa\"\n<strong>输出：</strong>[true,false,true,false,false]\n<strong>解释：</strong>\n\"FooBar\" 可以这样生成：\"Fo\" + \"o\" + \"Ba\" + \"r\".\n\"FootBall\" 可以这样生成：\"Fo\" + \"ot\" + \"Ba\" + \"ll\".\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>queries = [\"FooBar\",\"FooBarTest\",\"FootBall\",\"FrameBuffer\",\"ForceFeedBack\"], pattern = \"FoBaT\"\n<strong>输出：</strong>[false,true,false,false,false]\n<strong>解释： </strong>\n\"FooBarTest\" 可以这样生成：\"Fo\" + \"o\" + \"Ba\" + \"r\" + \"T\" + \"est\".\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= pattern.length, queries.length <= 100</code></li>\n\t<li><code>1 <= queries[i].length <= 100</code></li>\n\t<li><code>queries[i]</code> 和 <code>pattern</code> 由英文字母组成</li>\n</ul>\n",
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"hints": [
"Given a single pattern and word, how can we solve it?",
"One way to do it is using a DP (pos1, pos2) where pos1 is a pointer to the word and pos2 to the pattern and returns true if we can match the pattern with the given word.",
"We have two scenarios: The first one is when `word[pos1] == pattern[pos2]`, then the transition will be just DP(pos1 + 1, pos2 + 1). The second scenario is when `word[pos1]` is lowercase then we can add this character to the pattern so that the transition is just DP(pos1 + 1, pos2)\r\nThe case base is `if (pos1 == n && pos2 == m) return true;` Where n and m are the sizes of the strings word and pattern respectively."
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