{ "data": { "question": { "questionId": "3788", "questionFrontendId": "3487", "categoryTitle": "Algorithms", "boundTopicId": 3612270, "title": "Maximum Unique Subarray Sum After Deletion", "titleSlug": "maximum-unique-subarray-sum-after-deletion", "content": "

You are given an integer array nums.

\n\n

You are allowed to delete any number of elements from nums without making it empty. After performing the deletions, select a subarray of nums such that:

\n\n
    \n\t
  1. All elements in the subarray are unique.
  2. \n\t
  3. The sum of the elements in the subarray is maximized.
  4. \n
\n\n

Return the maximum sum of such a subarray.

\n\n

 

\n

Example 1:

\n\n
\n

Input: nums = [1,2,3,4,5]

\n\n

Output: 15

\n\n

Explanation:

\n\n

Select the entire array without deleting any element to obtain the maximum sum.

\n
\n\n

Example 2:

\n\n
\n

Input: nums = [1,1,0,1,1]

\n\n

Output: 1

\n\n

Explanation:

\n\n

Delete the element nums[0] == 1, nums[1] == 1, nums[2] == 0, and nums[3] == 1. Select the entire array [1] to obtain the maximum sum.

\n
\n\n

Example 3:

\n\n
\n

Input: nums = [1,2,-1,-2,1,0,-1]

\n\n

Output: 3

\n\n

Explanation:

\n\n

Delete the elements nums[2] == -1 and nums[3] == -2, and select the subarray [2, 1] from [1, 2, 1, 0, -1] to obtain the maximum sum.

\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "删除后的最大子数组元素和", "translatedContent": "

给你一个整数数组 nums 。

\n\n

你可以从数组 nums 中删除任意数量的元素,但不能将其变为 数组。执行删除操作后,选出 nums 中满足下述条件的一个子数组:

\n\n
    \n\t
  1. 子数组中的所有元素 互不相同
  2. \n\t
  3. 最大化 子数组的元素和。
  4. \n
\n\n

返回子数组的 最大元素和

\n子数组 是数组的一个连续、非空 的元素序列。\n\n

 

\n\n

示例 1:

\n\n
\n

输入:nums = [1,2,3,4,5]

\n\n

输出:15

\n\n

解释:

\n\n

不删除任何元素,选中整个数组得到最大元素和。

\n
\n\n

示例 2:

\n\n
\n

输入:nums = [1,1,0,1,1]

\n\n

输出:1

\n\n

解释:

\n\n

删除元素 nums[0] == 1nums[1] == 1nums[2] == 0 和 nums[3] == 1 。选中整个数组 [1] 得到最大元素和。

\n
\n\n

示例 3:

\n\n
\n

输入:nums = [1,2,-1,-2,1,0,-1]

\n\n

输出:3

\n\n

解释:

\n\n

删除元素 nums[2] == -1 和 nums[3] == -2 ,从 [1, 2, 1, 0, -1] 中选中子数组 [2, 1] 以获得最大元素和。

\n
\n\n

 

\n\n

提示:

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