You are given an integer array enemyEnergies denoting the energy values of various enemies.
You are also given an integer currentEnergy denoting the amount of energy you have initially.
You start with 0 points, and all the enemies are unmarked initially.
\n\nYou can perform either of the following operations zero or multiple times to gain points:
\n\ni, such that currentEnergy >= enemyEnergies[i]. By choosing this option:\n\n\tcurrentEnergy = currentEnergy - enemyEnergies[i].i. By choosing this option:\n\tcurrentEnergy = currentEnergy + enemyEnergies[i].i is marked.Return an integer denoting the maximum points you can get in the end by optimally performing operations.
\n\n\n
Example 1:
\n\nInput: enemyEnergies = [3,2,2], currentEnergy = 2
\n\nOutput: 3
\n\nExplanation:
\n\nThe following operations can be performed to get 3 points, which is the maximum:
\n\npoints increases by 1, and currentEnergy decreases by 2. So, points = 1, and currentEnergy = 0.currentEnergy increases by 3, and enemy 0 is marked. So, points = 1, currentEnergy = 3, and marked enemies = [0].points increases by 1, and currentEnergy decreases by 2. So, points = 2, currentEnergy = 1, and marked enemies = [0].currentEnergy increases by 2, and enemy 2 is marked. So, points = 2, currentEnergy = 3, and marked enemies = [0, 2].points increases by 1, and currentEnergy decreases by 2. So, points = 3, currentEnergy = 1, and marked enemies = [0, 2].Example 2:
\n\nInput: enemyEnergies = [2], currentEnergy = 10
\n\nOutput: 5
\n\nExplanation:
\n\nPerforming the first operation 5 times on enemy 0 results in the maximum number of points.
\n\n
Constraints:
\n\n1 <= enemyEnergies.length <= 1051 <= enemyEnergies[i] <= 1090 <= currentEnergy <= 109给你一个下标从 0 开始的整数数组 enemyEnergies ，它表示一个下标从 0 开始的敌人能量数组。
同时给你一个整数 currentEnergy ，它表示你一开始拥有的能量值总量。
你一开始的分数为 0 ，且一开始所有的敌人都未标记。
你可以通过以下操作 之一 任意次（也可以 0 次）来得分：
\n\ncurrentEnergy >= enemyEnergies[i] 的敌人 i 。在这个操作中：\n\n\t1 分。enemyEnergies[i] ，也就是说 currentEnergy = currentEnergy - enemyEnergies[i] 。1 分，你可以选择一个 未标记 的敌人 i 。在这个操作中：\n\tenemyEnergies[i] ，也就是说 currentEnergy = currentEnergy + enemyEnergies[i] 。i 被标记 。请你返回通过以上操作，最多 可以获得多少分。
\n\n\n\n
示例 1：
\n\n输入：enemyEnergies = [3,2,2], currentEnergy = 2
\n\n输出：3
\n\n解释：
\n\n通过以下操作可以得到最大得分 3 分：
\n\npoints 增加 1 ，currentEnergy 减少 2 。所以 points = 1 且 currentEnergy = 0 。currentEnergy 增加 3 ，敌人 0 被标记。所以 points = 1 ，currentEnergy = 3 ，被标记的敌人包括 [0] 。points 增加 1 ，currentEnergy 减少 2 。所以 points = 2 且 currentEnergy = 1 ，被标记的敌人包括[0] 。currentEnergy 增加 2 ，敌人 2 被标记。所以 points = 2 ，currentEnergy = 3 且被标记的敌人包括 [0, 2] 。points 增加 1 ，currentEnergy 减少 2 。所以 points = 3 ，currentEnergy = 1 ，被标记的敌人包括 [0, 2] 。示例 2：
\n\n输入：enemyEnergies = [2], currentEnergy = 10
\n\n输出：5
\n\n解释：
\n\n通过对敌人 0 进行第一种操作 5 次，得到最大得分。
\n\n\n\n
提示：
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