<p>Given an array of strings <code>words</code> and a string <code>s</code>, determine if <code>s</code> is an <strong>acronym</strong> of words.</p> <p>The string <code>s</code> is considered an acronym of <code>words</code> if it can be formed by concatenating the <strong>first</strong> character of each string in <code>words</code> <strong>in order</strong>. For example, <code>"ab"</code> can be formed from <code>["apple", "banana"]</code>, but it can't be formed from <code>["bear", "aardvark"]</code>.</p> <p>Return <code>true</code><em> if </em><code>s</code><em> is an acronym of </em><code>words</code><em>, and </em><code>false</code><em> otherwise. </em></p> <p> </p> <p><strong class="example">Example 1:</strong></p> <pre> <strong>Input:</strong> words = ["alice","bob","charlie"], s = "abc" <strong>Output:</strong> true <strong>Explanation:</strong> The first character in the words "alice", "bob", and "charlie" are 'a', 'b', and 'c', respectively. Hence, s = "abc" is the acronym. </pre> <p><strong class="example">Example 2:</strong></p> <pre> <strong>Input:</strong> words = ["an","apple"], s = "a" <strong>Output:</strong> false <strong>Explanation:</strong> The first character in the words "an" and "apple" are 'a' and 'a', respectively. The acronym formed by concatenating these characters is "aa". Hence, s = "a" is not the acronym. </pre> <p><strong class="example">Example 3:</strong></p> <pre> <strong>Input:</strong> words = ["never","gonna","give","up","on","you"], s = "ngguoy" <strong>Output:</strong> true <strong>Explanation: </strong>By concatenating the first character of the words in the array, we get the string "ngguoy". Hence, s = "ngguoy" is the acronym. </pre> <p> </p> <p><strong>Constraints:</strong></p> <ul> <li><code>1 <= words.length <= 100</code></li> <li><code>1 <= words[i].length <= 10</code></li> <li><code>1 <= s.length <= 100</code></li> <li><code>words[i]</code> and <code>s</code> consist of lowercase English letters.</li> </ul>