Given an undirected tree consisting of n vertices numbered from 0 to n-1, which has some apples in their vertices. You spend 1 second to walk over one edge of the tree. Return the minimum time in seconds you have to spend to collect all apples in the tree, starting at vertex 0 and coming back to this vertex.
The edges of the undirected tree are given in the array edges, where edges[i] = [ai, bi] means that exists an edge connecting the vertices ai and bi. Additionally, there is a boolean array hasApple, where hasApple[i] = true means that vertex i has an apple; otherwise, it does not have any apple.
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Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2020/04/23/min_time_collect_apple_1.png\")
\n\nInput: n = 7, edges = [[0,1],[0,2],[1,4],[1,5],[2,3],[2,6]], hasApple = [false,false,true,false,true,true,false]\nOutput: 8 \nExplanation: The figure above represents the given tree where red vertices have an apple. One optimal path to collect all apples is shown by the green arrows. \n\n\n
Example 2:
\n![\"\"](\"https://assets.leetcode.com/uploads/2020/04/23/min_time_collect_apple_2.png\")
\n\nInput: n = 7, edges = [[0,1],[0,2],[1,4],[1,5],[2,3],[2,6]], hasApple = [false,false,true,false,false,true,false]\nOutput: 6\nExplanation: The figure above represents the given tree where red vertices have an apple. One optimal path to collect all apples is shown by the green arrows. \n\n\n
Example 3:
\n\n\nInput: n = 7, edges = [[0,1],[0,2],[1,4],[1,5],[2,3],[2,6]], hasApple = [false,false,false,false,false,false,false]\nOutput: 0\n\n\n
\n
Constraints:
\n\n1 <= n <= 105edges.length == n - 1edges[i].length == 20 <= ai < bi <= n - 1hasApple.length == nCompiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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