Given the array nums, for each nums[i] find out how many numbers in the array are smaller than it. That is, for each nums[i] you have to count the number of valid j's such that j != i and nums[j] < nums[i].
Return the answer in an array.
\n\n\n
Example 1:
\n\n\nInput: nums = [8,1,2,2,3]\nOutput: [4,0,1,1,3]\nExplanation: \nFor nums[0]=8 there exist four smaller numbers than it (1, 2, 2 and 3). \nFor nums[1]=1 does not exist any smaller number than it.\nFor nums[2]=2 there exist one smaller number than it (1). \nFor nums[3]=2 there exist one smaller number than it (1). \nFor nums[4]=3 there exist three smaller numbers than it (1, 2 and 2).\n\n\n
Example 2:
\n\n\nInput: nums = [6,5,4,8]\nOutput: [2,1,0,3]\n\n\n
Example 3:
\n\n\nInput: nums = [7,7,7,7]\nOutput: [0,0,0,0]\n\n\n
\n
Constraints:
\n\n2 <= nums.length <= 5000 <= nums[i] <= 100Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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