An undirected graph of n nodes is defined by edgeList, where edgeList[i] = [ui, vi, disi] denotes an edge between nodes ui and vi with distance disi. Note that there may be multiple edges between two nodes.
Given an array queries, where queries[j] = [pj, qj, limitj], your task is to determine for each queries[j] whether there is a path between pj and qj such that each edge on the path has a distance strictly less than limitj .
Return a boolean array answer, where answer.length == queries.length and the jth value of answer is true if there is a path for queries[j] is true, and false otherwise.
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Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2020/12/08/h.png\")
\n\nInput: n = 3, edgeList = [[0,1,2],[1,2,4],[2,0,8],[1,0,16]], queries = [[0,1,2],[0,2,5]]\nOutput: [false,true]\nExplanation: The above figure shows the given graph. Note that there are two overlapping edges between 0 and 1 with distances 2 and 16.\nFor the first query, between 0 and 1 there is no path where each distance is less than 2, thus we return false for this query.\nFor the second query, there is a path (0 -> 1 -> 2) of two edges with distances less than 5, thus we return true for this query.\n\n\n
Example 2:
\n![\"\"](\"https://assets.leetcode.com/uploads/2020/12/08/q.png\")
\n\nInput: n = 5, edgeList = [[0,1,10],[1,2,5],[2,3,9],[3,4,13]], queries = [[0,4,14],[1,4,13]]\nOutput: [true,false]\nExplanation: The above figure shows the given graph.\n\n\n
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Constraints:
\n\n2 <= n <= 1051 <= edgeList.length, queries.length <= 105edgeList[i].length == 3queries[j].length == 30 <= ui, vi, pj, qj <= n - 1ui != vipj != qj1 <= disi, limitj <= 109Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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