You are given a 0-indexed string s consisting of only lowercase English letters, where each letter in s appears exactly twice. You are also given a 0-indexed integer array distance of length 26.
Each letter in the alphabet is numbered from 0 to 25 (i.e. 'a' -> 0, 'b' -> 1, 'c' -> 2, ... , 'z' -> 25).
In a well-spaced string, the number of letters between the two occurrences of the ith letter is distance[i]. If the ith letter does not appear in s, then distance[i] can be ignored.
Return true if s is a well-spaced string, otherwise return false.
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Example 1:
\n\n\nInput: s = "abaccb", distance = [1,3,0,5,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]\nOutput: true\nExplanation:\n- 'a' appears at indices 0 and 2 so it satisfies distance[0] = 1.\n- 'b' appears at indices 1 and 5 so it satisfies distance[1] = 3.\n- 'c' appears at indices 3 and 4 so it satisfies distance[2] = 0.\nNote that distance[3] = 5, but since 'd' does not appear in s, it can be ignored.\nReturn true because s is a well-spaced string.\n\n\n
Example 2:
\n\n\nInput: s = "aa", distance = [1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]\nOutput: false\nExplanation:\n- 'a' appears at indices 0 and 1 so there are zero letters between them.\nBecause distance[0] = 1, s is not a well-spaced string.\n\n\n
\n
Constraints:
\n\n2 <= s.length <= 52s consists only of lowercase English letters.s exactly twice.distance.length == 260 <= distance[i] <= 50Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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Python 2.7.12.
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