Create a class ArrayWrapper that accepts an array of integers in its constructor. This class should have two features:
+ operator, the resulting value is the sum of all the elements in both arrays.String() function is called on the instance, it will return a comma separated string surrounded by brackets. For example, [1,2,3].\n
Example 1:
\n\n\nInput: nums = [[1,2],[3,4]], operation = "Add"\nOutput: 10\nExplanation:\nconst obj1 = new ArrayWrapper([1,2]);\nconst obj2 = new ArrayWrapper([3,4]);\nobj1 + obj2; // 10\n\n\n
Example 2:
\n\n\nInput: nums = [[23,98,42,70]], operation = "String"\nOutput: "[23,98,42,70]"\nExplanation:\nconst obj = new ArrayWrapper([23,98,42,70]);\nString(obj); // "[23,98,42,70]"\n\n\n
Example 3:
\n\n\nInput: nums = [[],[]], operation = "Add"\nOutput: 0\nExplanation:\nconst obj1 = new ArrayWrapper([]);\nconst obj2 = new ArrayWrapper([]);\nobj1 + obj2; // 0\n\n\n
\n
Constraints:
\n\n0 <= nums.length <= 10000 <= nums[i] <= 1000Note: nums is the array passed to the constructor创建一个名为 ArrayWrapper 的类，它在其构造函数中接受一个整数数组作为参数。该类应具有以下两个特性：
+ 运算符将两个该类的实例相加时，结果值为两个数组中所有元素的总和。String() 函数时，它将返回一个由逗号分隔的括在方括号中的字符串。例如，[1,2,3] 。\n\n
示例 1：
\n\n\n输入：nums = [[1,2],[3,4]], operation = \"Add\"\n输出：10\n解释：\nconst obj1 = new ArrayWrapper([1,2]);\nconst obj2 = new ArrayWrapper([3,4]);\nobj1 + obj2; // 10\n\n\n
示例 2：
\n\n\n输入：nums = [[23,98,42,70]], operation = \"String\"\n输出：\"[23,98,42,70]\"\n解释：\nconst obj = new ArrayWrapper([23,98,42,70]);\nString(obj); // \"[23,98,42,70]\"\n\n\n
示例 3：
\n\n\n输入：nums = [[],[]], operation = \"Add\"\n输出：0\n解释：\nconst obj1 = new ArrayWrapper([]);\nconst obj2 = new ArrayWrapper([]);\nobj1 + obj2; // 0\n\n\n
\n\n
提示：
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"exampleTestcases": "[[1,2],[3,4]]\n\"Add\"\n[[23,98,42,70]]\n\"String\"\n[[],[]]\n\"Add\"",
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